Question

给出以下示例xml

<?xml version="1.0" encoding="utf-8" ?>
<CodeSamples>
   <CodeSample language="vba">
   <!--all values in ModifierString,Parameters & ReturnType should be in lowercase-->
     <MethodName>AddNewContact</MethodName>
     <ModifierString value="public sub" />
     <Parameters>
       <Parameter parameterType ="string" parameterName ="wholeName" />
       <Parameter parameterType ="string" parameterName ="email" />
       <Parameter parameterType ="string" parameterName ="mobileNumber" />
     </Parameters>
     <ReturnType>void</ReturnType>
     <CodeLines>
        Dim outlookContact As Outlook.ContactItem
        If outlookContact Is Nothing Then
            Set outlookContact = Application.CreateItem(olContactItem)
            With outlookContact
              .fullName = wholeName
              .Email1Address = email
              .Email1DisplayName = wholeName
              .MobileTelephoneNumber = mobileNumber
              .Save
          End With
      End If
      Set outlookContact = Nothing
     </CodeLines>
   </CodeSample>
</CodeSamples>

我正在尝试构建一个查询，以使用特定语言返回CodeSamples的所有实例，我遇到的问题是如何将参数列表放入查询中。到目前为止，这是查询，现在只是试图从xml文件中取出一个样本。

被修改

var codeSample =
        from element in xDoc.Element("CodeSamples")?.Elements("CodeSample")
        where element.Attribute("language")?.Value == "vba" && element.Element("MethodName")?.Value == methodName
        select new CodeSample()
        {
            Language = element.Attribute("language").Value,
            Modifiers = element.Element("ModifierString")?.Value,
            MethodName = methodName,
            ReturnType = element.Element("ReturnType")?.Value,
            CodeLines = element.Element("CodeLines")?.Value,
            Parameters = element.Element("Parameters")?.Elements()
                     .Select(x => new MethodParameters
                     {
                        ParameterName = x.Attribute("parameterName").‌Value,
                        ParameterType = x.Attribute("parameterType").Value
                     })
       };

MethodParameters是一个类

public class MethodParameters
{
    public string ParameterName { get; set; }
    public string ParameterType { get; set; }
}

任何帮助表示感谢。

最终工作代码感谢jdweng

var codeSamples = xDoc.Descendants("CodeSample").Where(x => (string)x.Attribute("language") == language)
            .Select(x => new  CodeSample
            {
                Language = x.Attribute("language").Value,
                Modifiers = x.Element("ModifierString")?.Value,
                MethodName = x.Element("MethodName")?.Value,
                ReturnType = x.Element("ReturnType")?.Value,
                Parameters = x.Descendants("Parameter").Select(y => new MethodParameters {
                    ParameterType = (string)y.Attribute("parameterType"),
                    ParameterName = (string)y.Attribute("parameterName")
                }).ToList(),
                CodeLines = (string)x.Element("CodeLines")
            });

Answer 1

试试xml linq

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication1
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            XDocument doc = XDocument.Load(FILENAME);

            var results = doc.Descendants("CodeSample").Where(x => (string)x.Attribute("language") == "vba").Select(x => new {
                parameters = x.Descendants("Parameter").Select(y => new {
                    parameterType = (string)y.Attribute("parameterType"),
                    parameterName = (string)y.Attribute("parameterName")
                }).ToList(),
                codeLines = (string)x.Element("CodeLines")
            }).ToList();

        }
    }
}

将项添加到查询中的列表中

1 个答案: