如何在JAVA中获取最后一行字符串

Question

$GPGGA,013810.000,1437.9098,N,12100.2297,E,1,10,1.0,26.4,M,39.1,M,,0000*69
$GPRMC,013810.000,A,1437.9098,N,12100.2297,E,0.00,122.34,200916,,,A*6A
$GPGGA,013811.000,1437.9098,N,12100.2297,E,1,10,1.0,26.4,M,39.1,M,,0000*69
$GPRMC,013811.000,A,1437.9098,N,12100.2297,E,0.00,122.34,200916,,,A*6A
$GPGGA,013812.000,1437.9098,N,12100.2297,E,1,10,1.0,26.4,M,39.1,M,,0000*69
$GPRMC,013812.000,A,1437.9098,N,12100.2297,E,0.00,122.34,200916,,,A*6A

每秒我将NMEA的字符串连接到字符串变量。我想要的是获得最后的$ GPGGA和GPRMC，因为我需要时间和日期。有没有办法做到这一点？先谢谢你们。

Answer 1

如果您有以下内容：

String a = "$GPGGA,013812.000,1437.9098,N,12100.2297,E,1,10,1.0,26.4,M,39.1,M,,0000*69";
String b = "$GPRMC,013812.000,A,1437.9098,N,12100.2297,E,0.00,122.34,200916,,,A*6A";

然后在“，”符号处分开：

String[] aAry = a.split(",");
String[] bAry = b.split(",");

我认为每个数组的第二个元素（索引1）包含时间，因此它可以作为aAry[1]访问，其中包含字符串013812.000（和bAry[1]一样）。我不确定这些字符串中存储日期的位置。