Question

我正在使用selenium + python，在python上使用隐式等待和try / except代码来捕获错误。但是我注意到如果浏览器崩溃（假设用户在程序执行期间关闭了浏览器），我的python程序将挂起，并且隐藏等待的超时似乎不起作用发生。以下过程将永远留在那里。

from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium import webdriver
import datetime
import time
import sys
import os

def open_browser():
    print "Opening web page..."

    driver = webdriver.Chrome()

    driver.implicitly_wait(1)
    #driver.set_page_load_timeout(30)
    return driver


driver = open_browser() # Opens web browser

# LET'S SAY I CLOSE THE BROWSER RIGHT HERE! 
# IF I CLOSE THE PROCESS HERE, THE PROGRAM WILL HANG FOREVER
time.sleep(5)
while True:
    try:
        driver.get('http://www.google.com')
        break
   except:
        driver.quit()
        driver = open_browser()

Answer 1

如果获取Google主页时出现异常，您提供的代码将始终挂起。可能发生的事情是，尝试获取谷歌主页会导致异常，通常会暂停程序，但是您正在使用except子句掩盖它。

尝试对您的循环进行以下修正。

max_attemtps = 10
attempts = 0
while attempts <= max_attempts:
    try:
        print "Retrieving google"
        driver.get('http://www.google.com')
        break
   except:
        print "Retrieving google failed"
        attempts += 1

如果Web浏览器在selenium中崩溃，进程会挂起

1 个答案: