Question

我试图将pyqtgraph嵌入到PyQt4 GraphicsView小部件中。我收到以下代码的错误：我做错了什么？

#imports
from PyQt4 import QtGui
from PyQt4 import QtCore
import ui_test  #Gui File
import sys
import pyqtgraph as pg


class Gui(QtGui.QMainWindow, ui_test.Ui_MainWindow, pg):
    vb = pg.ViewBox() 

    def __init__(self):        
        super(self.__class__, self).__init__()        
        self.setupUi(self)  # This is defined in ui_pumptest.py file automatically        
        self.graphicsView.setCentralItem(self.vb)   #set central item to be graph


def main():
    app = QtGui.QApplication(sys.argv)  # A new instance of QApplication
    form = Gui()  # We set the form to be our ExampleApp (design)
    form.show()  # Show the form
    app.exec_()  # and execute the. app

if __name__ == '__main__':  # if we're running file directly and not importing it
    main()  # run the main function

错误是：

QWidget: Must construct a QApplication before a QPaintDevice

Answer 1

需要使用此代码修复的两件事：（1）从基类列表中删除pg，不从整个pyqtgraph库继承：

class Gui(QtGui.QMainWindow, ui_test.Ui_MainWindow, pg):

到

class Gui(QtGui.QMainWindow, ui_test.Ui_MainWindow):

（2）在 init ：

中构建视图框

class Gui(QtGui.QMainWindow, ui_test.Ui_MainWindow):


    def __init__(self):        
        super(self.__class__, self).__init__()        
        self.setupUi(self)  # This is defined in ui_pumptest.py file automatically        
        self.vb = pg.ViewBox() 
        self.graphicsView.setCentralItem(self.vb)   #set central item to be graph

错误将Pyqtgraph嵌入到PyQt4 GraphicsView中

1 个答案: