Question

当我执行程序时，它会询问我的名字，如果我输了多个字母它有错误而且它关闭了，而在第二个字母中，我把它丢失并立即关闭

#include <stdio.h>

int main () {

   char firstname[20];
   char lastname[20];
   char response[20];

   printf ("Type your first name:\n");
   scanf ("'c'",&firstname);
   printf ("\n");  
   printf ("Type your last name:\n");
   scanf ("'c'",&lastname);
   printf ("\n");

   printf ("Hi %s %s do you want to stop giving me information?\nSay Y or  N");
   scanf ("%s",&response);

   if (response == 'Y' || response == 'y'); {
      system ("pause<NULL");
   }
   printf("Thank you for using my program. Good Bye!\n\n"); 

   system ("pause<NULL");
}

Answer 1

有很多问题：

你可能想要这个（未经测试的代码）

#include <stdio.h>

int main () {    
   char firstname[20];
   char lastname[20];
   char response[20];

   printf ("Type your first name:\n");
   scanf ("%s", firstname);
   printf ("\n");  
   printf ("Type your last name:\n");
   scanf ("%s", lastname);
   printf ("\n");

   printf ("Hi %s %s do you want to stop giving me information?\nSay Y or  N", firstname, lastname);
   scanf ("%s",response);

   if (response[0] == 'Y' || response[0] == 'y') {
      system ("pause<NULL");
   }
   printf("Thank you for using my program. Good Bye!\n\n"); 

   system ("pause<NULL");

   return 0;
}

没有'c'格式说明符，它是%s
scanf ("%s", &firstname)错误，firstname已经是缓冲区的地址
response == 'y'错了，response是缓冲区的地址，你只需要缓冲区的第一个字符，即responde[0]
if (response[0] == 'Y' || response[0] == 'y'); {，;

{

Answer 2

你的问题是你要求输入字符，你想要一个字符串。

tutorialspoint有一个simlpe和claean示例。 https://www.tutorialspoint.com/c_standard_library/c_function_scanf.htm

C使用char编程错误

2 个答案: