Question

NSMutableArray *array = [NSMutableArray arrayWithObjects:@"22,343", @"44,323",@"34,5678",@"22,725", nil];

我有这个数组，我想把这个数组的两个值相加。像这样array[0] + array [1]

如何总结这些元素？谢谢!!

Answer 1

解决方案

NSString *strVaue1 = [array[0] stringByReplacingOccurrencesOfString:@"," withString:@""];
NSString *strVaue2 = [array[1] stringByReplacingOccurrencesOfString:@"," withString:@""];
NSUInteger  arrValue1 = [strVaue1 integerValue];
NSUInteger  arrValue2 = [strVaue2 integerValue];
NSUInteger  sum = arrValue1 + arrValue2;
NSNumberFormatter *fmt = [[NSNumberFormatter alloc] init];
[fmt setNumberStyle:NSNumberFormatterDecimalStyle]; // to get commas (or locale equivalent)
[fmt setMaximumFractionDigits:0]; // to avoid any decimal
NSString *result = [fmt stringFromNumber:@(sum)];
NSLog(@"The result is - %@",result);

打印结果是

The result is - 66,666

如何将数组的两个元素相加？

1 个答案: