我有两个独立的阵列,我需要合并到第三个阵列,这样我就可以获得所需的所有数据。 基本上第一个数组有一个id和名称,为了获得我需要在第二个数组内搜索并匹配id的地址,所以我可以获得该人的所有数据。
以下是数据和代码:
//Array 1
var myPeopleArray = [{"people":[{"id":"123","name":"name 1"},{"id":"456","name":"name 2"}]}];
//Array 2
var myPersonArray = [{"person":[{"id":"123","address":"address 1"},{"id":"456","address":"address 2"}]}];
var arrayLength = myPeopleArray[0].people.length;
for (var i = 0; i < arrayLength; i++) {
console.log("id: " + myPeopleArray[0].people[i].id);
}
//Wanted Result:
[{"people":[
{
"id":"123",
"name":"name 1",
"address":"address 1"
},
{
"id":"456",
"name":"name 2",
"address":"address 2"
}
]
}]
我该怎么做?
答案 0 :(得分:1)
var myPeopleArray = [{"people":[{"id":"123","name":"name 1"}, {"id":"456","name":"name 2"}]}];
var myPersonArray = [{"person":[{"id":"123","address":"address 1"}, {"id":"456","address":"address 2"}]}];
for(var i=0;i<myPeopleArray[0].people.length;i++)
{
myPeopleArray[0].people[i].address = myPersonArray[0].person[i].address;
}
document.write(JSON.stringify(myPeopleArray));
答案 1 :(得分:0)
您可以迭代两个数组并使用连接的属性构建新对象。
var myPeopleArray = [{ "people": [{ "id": "123", "name": "name 1" }, { "id": "456", "name": "name 2" }] }],
myPersonArray = [{ "person": [{ "id": "123", "address": "address 1" }, { "id": "456", "address": "address 2" }] }],
hash = Object.create(null),
joined = [],
joinById = function (o) {
if (!(o.id in hash)) {
hash[o.id] = {};
joined.push(hash[o.id]);
}
Object.keys(o).forEach(function (k) {
hash[o.id][k] = o[k];
});
};
myPeopleArray[0].people.forEach(joinById);
myPersonArray[0].person.forEach(joinById);
console.log(joined);
&#13;