为什么语法`& name arg1 arg2 ...`不能用来调用Perl子程序?

时间:2016-09-21 07:37:28

标签: perl syntax subroutine invocation

对于Perl子例程,如果传递0参数,我可以使用4个表单来调用它。但是如果传递一个或多个参数,有一个我无法使用的表单,请参阅下面的内容:

sub name
{
    print "hello\n";
}
# 4 forms to call
name;
&name;
name();
&name();

sub aname
{
        print "@_\n";
}
aname "arg1", "arg2";
#&aname "arg1", "arg2"; # syntax error
aname("arg1", "arg2");
&aname("arg1", "arg2");

错误输出

String found where operator expected at tmp1.pl line 16, near "&aname "arg1""
    (Missing operator before  "arg1"?)
syntax error at tmp1.pl line 16, near "&aname "arg1""
Execution of tmp1.pl aborted due to compilation errors.

有人可以从编译器的角度解释错误输出吗?我不明白为什么抱怨缺少操作员。

由于

1 个答案:

答案 0 :(得分:13)

记录在perlsub

  

调用子程序:

       NAME(LIST);    # & is optional with parentheses.
       NAME LIST;     # Parentheses optional if predeclared/imported.
       &NAME(LIST);   # Circumvent prototypes.
       &NAME;         # Makes current @_ visible to called subroutine.

使用&NAME "arg",perl会看到&NAME() "ARG",因此它认为子调用与“ARG”之间缺少运算符。

在Perl 5中,大多数情况下您不需要&