Question

这是我的PHP代码

<?php

ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);

class stripeContact{
    public $ID;
    public $amount;
    public $amount_refunded;
    public $currency;
    public $profileName;
    public $profileID;
    public $fingerprint;
    public $cardEmail;
    public $createDate;
    public $description;
    public $paymentID;
    public $logID;

}

class set{
    private $stripeOb;

    function __construct($input){
        $input = (array) $input;
        var_dump($input);
        $this->stripeOb = new stripeContact();
        $this->stripeOb->ID = $input["id"];
        $this->stripeOb->amount = $input["amount"];
        $this->stripeOb->amount_refunded = $input["amount_refunded"];
        $this->stripeOb->description = $input["description"];
        $this->stripeOb->logID = "-999";
    } 

    public function stripe(){
        return new log($this);
    }
}

class log{
    private $dbTableName = "stripeLog";
    private $client;

    function __construct($client){
        $this->$client = $client;
    }

    public function save(){
    // save to sql code
    }
}
?>

并且在另一个php类中我正在调用类 set 。

$stripe = new set($onlinePay);
$resStripe = $stripe->stripe()->save();

当我打电话给我这个错误时

Catchable fatal error</b>:  Object of class set could not be converted to string in

此行中出现此错误

function __construct($client){
    $this->$client = $client;
}

我在做错了什么。我将整个 set 类实例传递给日志类中的构造函数。

Answer 1

 $this->$client = $client;
        ^

摆脱$，其他一切都很好。错字导致不必要的转换，从而产生错误。

Answer 2

您应该更改您的课程命名方式。 set是php中的保留字。

示例：

class setStripe {

}

而不是

class set {

}

希望它有所帮助。

类集的对象无法转换为字符串

2 个答案: