有没有一种简单的方法来获得带有北约语音字母的矢量？

Question

考虑以下向量

r

我希望在保留数字的同时用北约语音字母（alpha，bravo，charli等）替换这些字母。 LETTERS中是否有向量，类似于#define PIPELINE = 10; int server() { char *name = "someName"; zctx_t *ctx = zctx_new(); void *router = zsocket_new(ctx, ZMQ_ROUTER); zsocket_set_hwm(router, PIPELINE*2); if (0 == zsocket_connect(router, tcp://127.0.0.1:6000)) { printf("failed to connect to router.\n"); } printf( "sending name %s\n, name); zstr_sendfm( router, name ); return 0; } ，具有完整的北约语音字母？

Answer 1

我不知道内置列表。它只是一个单词的矢量，you can get it yourself。

NATO <- strsplit("Alfa, Bravo, Charlie, Delta, Echo, Foxtrot, Golf, Hotel, India, Juliett, Kilo, Lima, Mike, November, Oscar, Papa, Quebec, Romeo, Sierra, Tango, Uniform, Victor, Whiskey, X-ray, Yankee, Zulu", ", ")
z <- paste0(unlist(NATO),1:26)
z
#>  [1] "Alfa1"      "Bravo2"     "Charlie3"   "Delta4"     "Echo5"     
#>  [6] "Foxtrot6"   "Golf7"      "Hotel8"     "India9"     "Juliett10" 
#> [11] "Kilo11"     "Lima12"     "Mike13"     "November14" "Oscar15"   
#> [16] "Papa16"     "Quebec17"   "Romeo18"    "Sierra19"   "Tango20"   
#> [21] "Uniform21"  "Victor22"   "Whiskey23"  "X-ray24"    "Yankee25"  
#> [26] "Zulu26"