Question

您好我从Switch between two frames in tkinter的答案中获得了一些代码，我试图修改，因此StartPage类中的按钮可以在PageOne类中调用名为msg的函数。

但我得到了这个错误：

AttributeError：'Frame'对象没有属性'msg'

到目前为止，这是代码，我标出了对代码所做的修改。

import tkinter as tk   # python3
#import Tkinter as tk   # python

TITLE_FONT = ("Helvetica", 18, "bold")

class SampleApp(tk.Tk):

    def __init__(self, *args, **kwargs):
        tk.Tk.__init__(self, *args, **kwargs)

        # the container is where we'll stack a bunch of frames
        # on top of each other, then the one we want visible
        # will be raised above the others
        container = tk.Frame(self)
        container.pack(side="top", fill="both", expand=True)
        container.grid_rowconfigure(0, weight=1)
        container.grid_columnconfigure(0, weight=1)

        self.frames = {}
        for F in (StartPage, PageOne, PageTwo):
            page_name = F.__name__
            frame = F(parent=container, controller=self)
            self.frames[page_name] = frame

            # put all of the pages in the same location;
            # the one on the top of the stacking order
            # will be the one that is visible.
            frame.grid(row=0, column=0, sticky="nsew")

        self.show_frame("StartPage")

    def show_frame(self, page_name):
        '''Show a frame for the given page name'''
        frame = self.frames[page_name]
        frame.tkraise()


class StartPage(tk.Frame):

    def __init__(self, parent, controller):
        tk.Frame.__init__(self, parent)
        self.controller = controller

        self.parent = parent #<-- my mod

        label = tk.Label(self, text="This is the start page", font=TITLE_FONT)
        label.pack(side="top", fill="x", pady=10)

        button1 = tk.Button(self, text="Go to Page One",
                            command=lambda: controller.show_frame("PageOne"))
        button2 = tk.Button(self, text="Go to Page Two",
                            command=lambda: controller.show_frame("PageTwo"))
        self.button3 = tk.Button(text='Calling msg in another class', command=self.parent.msg)#<-- my mod
        button1.pack()
        button2.pack()
        button3.pack()#<-- my mod

class PageOne(tk.Frame):

    def __init__(self, parent, controller):
        tk.Frame.__init__(self, parent)
        self.controller = controller

        self.parent = parent #<-- my mod

        label = tk.Label(self, text="This is page 1", font=TITLE_FONT)
        label.pack(side="top", fill="x", pady=10)
        button = tk.Button(self, text="Go to the start page",
                           command=lambda: controller.show_frame("StartPage"))
        button.pack()

    def msg(self): #<-- my mod
        print("IT WORKS!!")

class PageTwo(tk.Frame):

    def __init__(self, parent, controller):
        tk.Frame.__init__(self, parent)
        self.controller = controller
        label = tk.Label(self, text="This is page 2", font=TITLE_FONT)
        label.pack(side="top", fill="x", pady=10)
        button = tk.Button(self, text="Go to the start page",
                           command=lambda: controller.show_frame("StartPage"))
        button.pack()


if __name__ == "__main__":
    app = SampleApp()
    app.mainloop()

有人可以帮帮我吗？

Answer 1

由于您在循环中实例化所有类，因此在它们之间添加引用的最简单方法可能是在该循环之后执行。从类中删除这些引用，因为它们在实例化之后才会生效。请注意button3中不再创建或打包StartPage的方式，而是放在SampleApp中。

for F in (StartPage, PageOne, PageTwo):
    ...

self.frames['StartPage'].pageone = self.frames['PageOne']
self.frames['StartPage'].button3 = tk.Button(
                                text='Calling msg in another class',
                                command=self.frames['StartPage'].pageone.msg) #<-- my mod
self.frames['StartPage'].button3.pack() #<-- my mod

Tkinter在另一个类中调用函数

1 个答案: