Question

Elasticsearch不支持版本控制，所以我自己使用这个好答案的方法＃3实现了它：https://stackoverflow.com/a/8226684/4769188。

现在我想要检索日期范围[from..to]的某些类型的所有版本，并且只获取每个文档的最新版本。我怎么能这样做？

Answer 1

看看这是否有帮助......

我索引了以下文件：

jdb

使用以下查询。这应该返回文档的第3版。 “top_hits”中的“size”参数确定每个桶的文档数量。（现在它设置为1）。

    {
  "took": 2,
  "timed_out": false,
  "_shards": {
    "total": 5,
    "successful": 5,
    "failed": 0
  },
  "hits": {
    "total": 4,
    "max_score": 1,
    "hits": [
      {
        "_index": "test_index",
        "_type": "test",
        "_id": "2",
        "_score": 1,
        "_source": {
          "doc_id": 123,
          "version": 2,
          "text": "Foo Bar",
          "date": "2011-09-01",
          "current": false
        }
      },
      {
        "_index": "test_index",
        "_type": "test",
        "_id": "4",
        "_score": 1,
        "_source": {
          "doc_id": 123,
          "version": 4,
          "text": "Foo Bar",
          "date": "2011-07-01",
          "current": false
        }
      },
      {
        "_index": "test_index",
        "_type": "test",
        "_id": "1",
        "_score": 1,
        "_source": {
          "doc_id": 123,
          "version": 1,
          "text": "Foo Bar",
          "date": "2011-10-01",
          "current": true
        }
      },
      {
        "_index": "test_index",
        "_type": "test",
        "_id": "3",
        "_score": 1,
        "_source": {
          "doc_id": 123,
          "version": 3,
          "text": "Foo Bar",
          "date": "2011-08-01",
          "current": false
        }
      }
    ]
  }}

响应：

{
    "size" : 0,
    "query" : {
        "filtered" : {
            "query" : {
                "match_all" : {}
            },
            "filter" : {
                "range" : {
                    "date" : {
                        "gte" : "2011-07-02",
                        "lte" : "2011-09-01"
                    }
                }
            }
        }
    },
    "aggs" : {
        "doc_id_groups" : {
            "terms" : {
                "field" : "doc_id",
                "size" : "10",
                "order" : {
                    "top_score" : "desc"
                }
            },
            "aggs" : {
                "top_score" : {
                    "max" : {
                        "script" : "_score"
                    }
                },
                "docs" : {
                    "top_hits" : {
                        "size" : 1,
                        "sort" : {
                            "version" : {
                                "order" : "desc"
                            }
                        },
                        "fields" : ["doc_id", "version", "date"]
                    }
                }
            }
        }
    }
}
}

检索每个文档的最新版本

1 个答案: