Question

我有一个Postgres函数，我需要检查特定值是否在时间戳数组中。这是功能：

CREATE OR REPLACE FUNCTION public.get_appointments(
     for_business_id INTEGER,
     range_start DATE,
     range_end   DATE,
     for_staff_id INTEGER
    )
       RETURNS SETOF appointment
       LANGUAGE plpgsql STABLE
       AS $function$
     DECLARE
        appointment appointment;
        recurrence  TIMESTAMP;
        appointment_length INTERVAL;
        parent_id UUID;
     BEGIN
        FOR appointment IN
            SELECT *
              FROM appointment
             WHERE business_id = for_business_id
               AND (
                       recurrence_pattern IS NOT NULL
                   OR  (
                          recurrence_pattern IS NULL
                      AND starts_at BETWEEN range_start AND range_end
                   )
               )
         LOOP
            IF appointment.recurrence_pattern IS NULL THEN
              RETURN NEXT appointment;
              CONTINUE;
            END IF;

            appointment_length := appointment.ends_at - appointment.starts_at;
            parent_id := appointment.id;

            FOR recurrence IN
                SELECT *
                  FROM generate_recurrences(
                           appointment.recurrence_pattern,
                           appointment.starts_at,
                           range_start,
                           range_end
                  )
            LOOP
                EXIT WHEN recurrence::date > range_end;
                -- THIS IS THE LINE IN QUESTION
                CONTINUE WHEN recurrence::date < range_start OR recurrence = ANY(appointment.recurrence_exceptions);
                appointment.id := uuid_generate_v5(uuid_nil(), parent_id::varchar || recurrence::varchar);
                appointment.parent_id := parent_id;
                appointment.starts_at := recurrence;
                appointment.ends_at := recurrence + appointment_length;
                appointment.recurrence_pattern := appointment.recurrence_pattern;
                appointment.recurrence_exceptions := NULL;
                appointment.is_recurrence := true;
                RETURN NEXT appointment;
            END LOOP;
        END LOOP;
        RETURN;
     END;
    $function$;

您会在第二个LOOP语句之后看到，有一个CONTINUE语句。我希望跳过循环的迭代，如果recurrence（这是时间戳，但是text格式）变量超出范围或者如果它被列为appointment的一部分'recurrence_exceptions数组。 recurrence_exceptions数组包含timestamp s。

这个想法是，如果约会被列为例外，则不会返回。不幸的是，无论我做什么，似乎ANY运算符都没有按预期工作。为了测试这一点，我从recurrence_exception数组中取出了一个值并将CONTINUE语句更改为：

CONTINUE WHEN recurrence::date < range_start OR recurrence = '2016-09-20 18:07:26';

这并没有像预期的那样恢复那种复发。

我是否正确使用了这个？

谢谢！

postgres：在时间戳数组上使用ANY

0 个答案: