Question

我写了以下查询，但它在运行总计中没有用专栏，我需要下面提到的日期和每个ID的所有记录，我前21天需要累计总数和21天的记录数天，在oracle中执行

SELECT (TO_DATE (MIN (date_ref_key), 'YYYYMMDD')),
       id,
       (TO_DATE (MIN (date_ref_key), 'YYYYMMDD')) + 21,
       SUM (
          Deposit_Amount)
       OVER (PARTITION BY id
             ORDER BY (TO_DATE (MIN (date_ref_key), 'YYYYMMDD')) <(to_date(min(date_ref_key),'YYYYMMDD'))+21) running_total
     from performance.fact_paymentsystems@cis_prod_link
      WHERE sort='Deposit' and
     date_ref_key>=20140831 and date_ref_key<20160901
     and status='Done'
     GROUP BY ID
     order by min(date_ref_key)

输入

id  date_ref_key    Amount
1   01/09/2014  10
1   02/09/2014  10
1   03/09/2014  10
1   04/09/2014  10
1   05/09/2014  10
1   06/09/2014  10
1   07/09/2014  10
1   08/09/2014  10
1   09/09/2014  10
1   10/09/2014  10
1   11/09/2014  10
1   12/09/2014  10
1   13/09/2014  10
1   14/09/2014  10
1   15/09/2014  10
1   16/09/2014  10
1   17/09/2014  10
1   18/09/2014  10
1   19/09/2014  10
1   20/09/2014  10
1   21/09/2014  10
1   22/09/2014  10
1   23/09/2014  10
1   24/09/2014  10
2   01/09/2014  10
2   02/09/2014  10
2   01/09/2012  10
2   02/09/2012  10
2   03/09/2012  10
2   04/09/2012  10
2   05/09/2012  10
2   06/09/2012  10
2   07/09/2012  10
2   08/09/2012  10
2   09/09/2012  10
2   10/09/2012  10
2   11/09/2012  10
2   12/09/2012  10
2   13/09/2012  10
2   14/09/2012  10
2   15/09/2012  10
2   16/09/2012  10
2   17/09/2012  10
2   18/09/2012  10
2   19/09/2012  10
2   20/09/2012  10
2   21/09/2012  10
2   22/09/2012  10
3   01/01/2015  10
3   02/01/2015  10
3   03/01/2015  10
3   04/01/2015  10
3   05/01/2015  10
3   06/01/2015  10
3   07/01/2015  10
3   08/01/2015  10
3   09/01/2015  10
3   10/01/2015  10
3   11/01/2015  10
3   12/01/2015  10
3   13/01/2015  10
3   14/01/2015  10
3   15/01/2015  10
3   16/01/2015  10
3   17/01/2015  10
3   18/01/2015  10
3   19/01/2015  10
3   20/01/2015  10
3   21/01/2015  10
3   22/01/2015  10
3   23/01/2015  10
3   24/01/2015  10

输出

ID  Amount COUNTOF IDS'S (SHOULD ALSO COUNT DUPLICATES IF PRESENT)
1   210   21
3   210   21

oracle中的累积逻辑与日期

0 个答案: