- <SAPAccounts> <SAPAccount ChargeNumber="0FPT15068806"
WSDescription="CCEC 32 - Rotor Standstill Inspection" /> <SAPAccount
ChargeNumber="dfgdfgfgg" WSDescription="gfghfghfhhs" />
</SAPAccounts>
我想将xml转换为不同类型的xml。我想访问多个子节点值。
<AddChargeNumberIDto>
<SAP>
<ChargeNumber>0FPT15068806</ChargeNumber>
<Description>CCEC 32 - Rotor Standstill Inspection</Description>
<SAP>
<SAP>
<ChargeNumber>dfgdfgfgg</ChargeNumber>
<Description>gfghfghfhhs</Description>
<SAP>
</AddChargeNumberIDto>
答案 0 :(得分:0)
以下样式表:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="SAPAccounts">
<AddChargeNumberIDto>
<xsl:for-each select="SAPAccount">
<SAP>
<ChargeNumber>
<xsl:value-of select="@ChargeNumber"/>
</ChargeNumber>
<Description>
<xsl:value-of select="@WSDescription"/>
</Description>
</SAP>
</xsl:for-each>
</AddChargeNumberIDto>
</xsl:template>
</xsl:stylesheet>
应用于输入示例时,将返回预期结果:
<?xml version="1.0" encoding="UTF-8"?>
<AddChargeNumberIDto>
<SAP>
<ChargeNumber>0FPT15068806</ChargeNumber>
<Description>CCEC 32 - Rotor Standstill Inspection</Description>
</SAP>
<SAP>
<ChargeNumber>dfgdfgfgg</ChargeNumber>
<Description>gfghfghfhhs</Description>
</SAP>
</AddChargeNumberIDto>
注意:您的样式表引用OpenJobInfo
- 但您的输入中没有此类元素。