UIApplicationOpenSettingsURLString在iOS 10中不起作用

Question

在 iOS 10 中，请勿打开设置网址：

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]];

有什么问题？

Answer 1

我确实喜欢这样，而且很有效。我今天正在测试它！

 NSURL *url = [NSURL URLWithString:UIApplicationOpenSettingsURLString];
 [[UIApplication sharedApplication] openURL:url];

斯威夫特3：

let urlObj = NSURL.init(string:UIApplicationOpenSettingsURLString)
if #available(iOS 10.0, *) {
    UIApplication.shared.open(urlObj as! URL, options: [ : ], completionHandler: { Success in

     })
} else {
      let success = UIApplication.shared.openURL(url as URL)
      print("Open \(url): \(success)")                            
}

Answer 2

雨燕4

if let url = URL(string: UIApplicationOpenSettingsURLString) {
   if UIApplication.shared.canOpenURL(url) {
      _ =  UIApplication.shared.open(url, options: [:], completionHandler: nil)
   }
}

Answer 3

对于iOS 11 +

UIApplication *application = [UIApplication sharedApplication];
NSURL *URL = [NSURL URLWithString:UIApplicationOpenSettingsURLString];
[application openURL:URL options:@{} completionHandler:^(BOOL success) {
    if (success) {
        NSLog(@"Opened url");
    }
}];

Answer 4

Apple Swift 5.3 版：

  if let url = URL(string: UIApplication.openSettingsURLString),  UIApplication.shared.canOpenURL(url){
         UIApplication.shared.open(url, options: [:], completionHandler: nil)
  }