如何在不使用jQuery的情况下将对象转换为对象数组？

Question

如何将此对象转换为包含对象的数组？

beacons = {
    "key": {
        "one": "char",
        "two": "sue",
        "three": "johnny"
    },
    "key2": {
        "one": "char",
        "two": "sue",
        "three": "johnny"
    },
    "key3": {
        "one": "char",
        "two": "cara",
        "three": "johnny"
    }
}

结果应该如下所示，我应该用这样的方式调用属性： beaconsArray [1] .one ---＆gt; ＆＃34;炭＆＃34;

beaconsArray = [{
    "one": "char",
    "two": "sue",
    "three": "johnny"
}, {
    "one": "char",
    "two": "sue",
    "three": "johnny"
}, {
    "one": "char",
    "two": "sue",
    "three": "johnny"
}]

Answer 1

#include "stdafx.h"

#pragma comment(lib, "cryptopp.lib)

using namespace CryptoPP;

int _tmain(int argc, _TCHAR* argv[])
{
    return 0;
}

Answer 2

您可以使用单个Array#map进行迭代。

为了获得稳定的结果，您可能需要先对键进行排序。

var beacons = { "key": { "one": "char", "two": "sue", "three": "johnny" }, "key2": { "one": "char", "two": "sue", "three": "johnny" }, "key3": { "one": "char", "two": "cara", "three": "johnny" } },
    array = Object.keys(beacons).sort().map(function (k) { return beacons[k]; });

console.log(array);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 3

类似的东西：

var beacons = { "key": { "one": "char", "two": "sue", "three": "johnny" }, "key2": { "one": "char", "two": "sue", "three": "johnny" }, "key3": { "one": "char", "two": "cara", "three": "johnny" } }
var result = [];

for (key in beacons) {
  result.push(beacons[key]);
}

console.log(result);

Answer 4

Object.values会为你做这件事。

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