Question

我在显示SQL结果时遇到问题。

我有两个变量必须在搜索数据库之前收到它们的值。

我想在数据库中搜索并使用简单的分页显示结果。我试过这里的一些代码是第一次运行良好，但是当你移动到下一页时没有显示下一个结果。我认为当你再次加载页面时，值变量变为null。 index.php发送变量值（用户的选择是什么） index1.php带有分页的结果这个完整的index1代码：

<?
$dtype = $_POST['dtype'];
$city = $_POST['city'];

$cor = mysql_query(" SELECT * FROM drivers  WHERE dtype='$dtype' AND city='$city' " );
$pr=mysql_fetch_array($cor); 
$orderid = $pr[ID];

if (!empty($city)) {
$rec_limit = 2;

/* Get total number of records */
$sql = "SELECT count(ID) FROM drivers  WHERE dtype='$dtype' AND city='$city' ";
$retval = mysql_query( $sql );
if(! $retval )
{
  die('Could not get data: ' . mysql_error());
}
$row = mysql_fetch_array($retval, MYSQL_NUM );
$rec_count = $row[0];

if( isset($_GET{'page'} ) )
{
   $page = $_GET{'page'} + 1;
   $offset = $rec_limit * $page ;
}
else
{
   $page = 0;
   $offset = 0;
}
$left_rec = $rec_count - ($page * $rec_limit);

$sql = "SELECT ID, dname, dtype,mobile,city ".
       "FROM drivers WHERE dtype='$dtype' AND city='$city'".
       "LIMIT $offset, $rec_limit";

$retval = mysql_query( $sql);
if(! $retval )
{
  die('Could not get data: ' . mysql_error());
}
while($row = mysql_fetch_array($retval, MYSQL_ASSOC))
{
?>
<ul data-role='listview' data-inset='true' class='ui-listview ui-listview-inset ui-corner-all ui-shadow'>

<div data-role="footer">

<ul data-role="listview" data-inset='true' class='ui-listview ui-listview-inset ui-corner-all ui-shadow'>
    <li>ID : <?echo $row[ID];?></li>
    <li>NAME : <?echo $row[dname];?></li> 
    <li>TYPE : <?echo $row[dtype];?></li>
    <li>CITY : <?echo $row[city];?></li>
</ul>

<?     
$sid = $row[ID];

} 

if( $page > 0  )
{
   $last = $page - 2;
   echo "<a href=\"$_PHP_SELF?page=$page\""?>data-ajax="false" class="ui-btn ui-corner-all ui-btn-inline ui-mini footer-button-right ui-btn-icon-right ui-icon-carat-l"> Next </a><?
  echo "<a href=\"$_PHP_SELF?page=$last\""?>data-ajax="false" class="ui-btn ui-corner-all ui-btn-inline ui-mini footer-button-right ui-btn-icon-right ui-icon-carat-r"> Previous </a><?

   }
else if( $page == 0 )
{
   echo "<a href=\"$_PHP_SELF?page=$page\""  .$city.""?>data-ajax="false" class="ui-btn ui-corner-all ui-btn-inline ui-mini footer-button-right ui-btn-icon-right ui-icon-carat-l"> Next </a><?

}
else if( $left_rec < $rec_limit )
{
   $last = $page - 2;
   echo "<a href=\"$_PHP_SELF?page=$last\">Last </a>";
}
}
else{

echo '
 <ul data-role="listview">

<li> can not view records </li>

</ul>

';}

?>

使用简单的分页显示SQL结果

0 个答案: