Question

是否可以<?php if(isset($_REQUEST['submit_album'])) { $album_titlee=$_REQUEST['album_titlee']; $user_id=$_SESSION['ses_userid']; $sql=mysqli_query($conn,"INSERT INTO tbl_album(user_id,album_title,album_status) VALUES ('".$user_id."','$album_titlee','Y')"); echo("<script type='text/javascript'>$.colorbox({inline:true,width:'50%', href:'#inline_content'});</script>"); } ?> foreach的结果只有一次？这就是我想要实现的目标：

echo

我的代码

18-sept-2016 | 08:00 AM | some text
               11:00 AM | some text
19-sept-2016 | 09:00 AM | some text
               09:10 AM | some text
               12:00 AM | some text

我目前的结果：

<?php if (!empty($notification)): ?>
            <table class="table" id="notification_table">
                <tbody>
                    <?php foreach ($notification as $row): ?>
                        <tr>
                            <td nowrap>
                                <?php echo date('d M',strtotime($row['created_on'])) ?>
                            </td>
                            <td><?php echo date('h:m A', strtotime($row['created_on'])) ?></td>
                            <td>
                                <?php echo $row['notification_text'] ?>
                            </td>
                        </tr>
                        <?php endforeach ?>
                </tbody>
            </table>
            <?php else: ?>
                <div class="alert alert-warning">
                    No notification
                </div>
            <?php endif ?>

我觉得如果我18-sept-2016 | 08:00 AM | some text 18-sept-2016 | 11:00 AM | some text 19-sept-2016 | 09:00 AM | some text 19-sept-2016 | 09:10 AM | some text 19-sept-2016 | 12:00 AM | some text只有一次日期，它看起来比我目前的效果更有效，但我不知道怎么做

Answer 1

简单就像这样：

    $dates = [];
    foreach ($notification as $row)

         $date = date('d M',strtotime($row['created_on']));
         if( !in_array($dates, $date ) ){
             echo $date;
             $dates[] = $date;
         }
      .....
   }

检查数据是否在日期数组中，如果没有，则回显并将其存储在日期数组中以供下次使用。

Answer 2

另一种方法是在temp变量中保存最后一个日期，并将其与当前迭代日期进行比较：

<?php if (!empty($notification)):
$date = ''; ?>
<table class="table" id="notification_table">
    <tbody>
        <?php foreach ($notification as $row): ?>
        <tr>
            <td nowrap>
            <?php if($date != $row['created_on']){
                echo date('d M',strtotime($row['created_on']));
                $date = $row['created_on'];
            } ?>
            </td>
            <td><?php echo $row['notification_text'] ?></td>
        </tr>
        <?php endforeach ?>
    </tbody>
</table>
<?php else: ?>
    <div class="alert alert-warning">No notification</div>
<?php endif ?>

Answer 3

首先初始化一个像$is_same_date = ''这样的变量空白，我按以下方式做出答案，因为你的数据是序列化的。

制作if条件以检查您的数据是否已打印，如果它在$is_same_date中，则无需再次显示日期，否则您必须显示日期并将日期存储到{{ 1}}。

$is_same_date

Answer 4

你可以用这种方式获得它

          <tbody>
               <!-- define $previous_value variable here to keep tmp value -->
                <?php $previous_value = ""; ?>
                <?php foreach ($notification as $row): ?>
                    <tr>
                        <td nowrap>
                            <?php 
                            if($previous_value != $row['created_on']){
                            echo date('d M',strtotime($row['created_on']));
                            }
                            $previous_value = $row['created_on'];
                            ?>
                        </td>
                        <td><?php echo date('h:m A', strtotime($row['created_on'])) ?></td>
                        <td>
                            <?php echo $row['notification_text'] ?>
                        </td>
                    </tr>
                    <?php endforeach ?>
            </tbody>

Answer 5

这将有助于日期未在输入数组中排序，如下所示：

<?php
$notification=array(0=>array('created_on'=> '18-sept-2016 08:00 AM','notification_text'=>'some text1'),
                    1=>array('created_on'=> '19-sept-2016 09:10 AM','notification_text'=>'some text2'),
                    2=>array('created_on'=> '19-sept-2016 09:00 AM','notification_text'=>'some text3'),
                    3=>array('created_on'=> '18-sept-2016 11:00 AM','notification_text'=>'some text4'),
                    4=>array('created_on'=> '19-sept-2016 12:00 AM','notification_text'=>'some text5'));

$new_array=array();
foreach($notification as $index => $value){
     $item=array();
     $item['time']=date('h:m A', strtotime($value['created_on'])); 
     $item['text']=$value['notification_text'];
     $new_array[date('d M',strtotime($value['created_on']))][]=$item;
}
?>
<?php if (!empty($new_array)): ?>
            <table class="table" id="notification_table">
                <tbody>
                    <?php foreach ($new_array as $index=>$row): ?>
                        <?php foreach ($row as $index_item=>$row_item): ?>
                        <tr>
                            <td nowrap>
                                <?php if($index_item ==0) echo $index ?>
                            </td>
                            <td><?php echo $row_item['time'] ?></td>
                            <td>
                                <?php echo $row_item['text'] ?>
                            </td>
                        </tr>
                          <?php endforeach ?>
                        <?php endforeach ?>
                </tbody>
            </table>
            <?php else: ?>
                <div class="alert alert-warning">
                    No notification
                </div>
            <?php endif ?>

我怎样才能只回显一次foreach迭代

5 个答案: