Question

你好麻烦在这里总是显示错误不知道为什么请帮助我我想在user_id和section_id中插入相同的差异，如此

from_id = 1 , assigned_for = 8 , user_id = 2, section_id = 1, month= january
from_id = 1 , assigned_for = 8 , user_id = 3, section_id = 3, month= january
from_id = 1 , assigned_for = 8 , user_id = 4, section_id = 4, month= january
from_id = 1 , assigned_for = 8 , user_id = 5, section_id = 5, month= january

在视图文件

中

下降数月。选择员工的下拉列表。标题允许权限以及仅名称带有复选框的部分以及从标题允许权限中提取的名称下拉列表。

控制器功能

 $from = $this->_user['user_id'];
            if ($this->form_validation->run() == TRUE) {
            if ($select_section_ids) {
                foreach ($select_section_ids as $id) {$data = array(
                                'from_id' => $from,
                                'assigned_for' =>$this->input->post('assigned_for') ,
                                'user_id' => $this->input->post('user_names'),
                                'section_id' => $id,
                                'month' => $this->input->post('month'),
                            );

            $this->my_model->insert($data);
}}

'from_id' - 是登录ID 'assigned_for' - 来自精选员工的下拉列表 'user_id' - 从允许权限下拉名称 'section_id' - 来自复选框 '月' - 来自下拉

如何插入此m有错误：列'user_id'不能为空

Answer 1

您对用户ID使用了错误的索引名称，asyncContext.start { while(true) { // write event } }是一个数组且等于team_lead，因此您可以使用section_ids的$ key来获取正确的section_ids。

示例：

team_leads

另请注意，如果<?php foreach ($select_section_ids as $key => $id) { $data = array( 'from_id' => $from, 'assigned_for' => (isset($_POST['assigned_for']) ? $_POST['assigned_for'] : 0), 'user_id' => $_POST['team_leads'][$key], // this will use the key of section_ids, which is equal to team_leads. 'section_id' => $id, 'month' => $_POST['month'], ); ?>不等于team_leads，则必须添加以下支票：

section_ids

如何在codeigniter中的控制器中传递foreach中的下拉值

1 个答案: