Question

我已经被困在这几个小时了，我需要将一个字符串连接到另一个字符串的末尾，然后将结果存储在第三个字符串中（不使用预先构建的函数。我有一个我试图将我的结果存储到另一个字符串中的困难时期，我能够看到我想要的东西，但是它会导致无限循环并且似乎没有效果。任何人都可以对此有所启发吗？

#include <iostream>

using namespace std;

void Concat(char arr1[], char arr2[], char arr3[]);

int main(){

    char arr1[] = {"Hello how are you? \0 "};
    char arr2[] = { "The weather was cloudy today, so it rained. \0" };
    char arr3[] = { "Coffee is a great way to start the day. \0" };

    Concat(arr1, arr2, arr3);
}

void Concat(char arr1[], char arr2[], char arr3[]){

    while (arr1 != '\0' && arr2 != '\0') {

        // (This outputs what a want, haveing string 2 concat to the end of the firs string) 
        // However there is no way to save it to another array or stop the infinte loop.
        //cout << arr1 << arr2 << endl; 

        arr1 + arr2 = arr3; // syntax error

    }


}

Answer 1

快速解决您的问题：

void Concat(const char* input1, const char* input2, char* output)
{
    int i = 0;
    do {

        output[i] = *input1;
        i++;
        input1++;
    } while (*input1 != '\0');
    do {

        output[i] = *input2;
        i++;
        input2++;
    } while (*input2 != '\0');
}

注意：我不检查输出缓冲区是否有足够的内存，我希望您可以自己编辑它。

Answer 2

您可能想尝试这样：

#include <iostream>

void concat(const char *arr1, const char *arr2, char *arr3);

int main(){
    const char *arr1("abc");
    const char *arr2("def");
    char arr3[10];

    concat(arr1, arr2, arr3);
    std::cout << "arr3 is " << arr3 << std::endl;
}

void concat(const char *arr1, const char *arr2, char *arr3){

    if (arr1) {
        while(*arr1 != '\0') {
            *arr3 = *arr1;
            ++arr1; ++arr3;
        }
    }

    if (arr2) {
        while(*arr2 != '\0') {
            *arr3 = *arr2;
            ++arr2; ++arr3;
        }
    }

    *arr3 = '\0';
}

Answer 3

您应该尝试按索引连接索引。在以下代码中，我首先在arr1中添加arr3的所有内容，然后arr2 concat的内容添加arr3

#include <iostream>

using namespace std;

void Concat(char arr1[], char arr2[], char arr3[]);

int main(){

    char arr1[] = {"Hello how are you? \0 "};
    char arr2[] = { "The weather was cloudy today, so it rained. \0" };
    char arr3[] = { "Coffee is a great way to start the day. \0" };

    Concat(arr1, arr2, arr3);
    std::cout << "arr3 is " << arr3 << std::endl;
}

void Concat(char arr1[], char arr2[], char arr3[]){

   if (arr1) {
        while(*arr1 != '\0') {
            *arr3 = *arr1;
            ++arr1; ++arr3;
        }
    }

    if (arr2) {
        while(*arr2 != '\0') {
            *arr3 = *arr2;
            ++arr2; ++arr3;
        }
    }

    *arr3 = '\0';


}

将char数组连接到另一个char数组的末尾（没有内置函数）

3 个答案: