提前感谢您提供的任何帮助。我希望获得存储在同一列中的事件之间的日期差异。参考样本数据，我正在寻找＆＃34;部分提交＆＃34;和他们随后的＆＃34; Jr评论＆＃34;事件。
再次引用相同的数据，我需要来自
的dateDiff我不知道从哪里开始，我所做的只是添加由＆＃34; Descrip＆＃34;分隔的rownumbers。由＆＃34;日期＆＃34;命令ASC。任何形式的指导或方法（递归CTE？）这将非常感激。
答案 0 :(得分：1)
DECLARE @Tbl TABLE (RowNumber INT, RecordNumber INT, IDX INT, DESCRIP NVARCHAR(50), DATES DATETIME, EVENTNUM INT)
INSERT INTO @Tbl
VALUES
(1, 11515, 13, 'Partial Submission', '8/12/16 00:21', 3078),
(1, 11515, 14, 'Junior Reviewed', '8/12/16 15:52', 3089),
(2, 11515, 26, 'Partial Submission', '8/18/16 15:24', 3078),
(3, 11515, 33, 'Partial Submission', '9/6/16 9:47', 3078),
(4, 11515, 34, 'Partial Submission', '9/6/16 9:47', 3078),
(5, 11515, 39, 'Partial Submission', '9/9/16 13:19', 3078),
(2, 11515, 40, 'Junior Reviewed', '9/11/16 8:30', 3089),
(6, 11515, 46, 'Partial Submission', '9/15/16 12:30', 3078),
(3, 11515, 54, 'Junior Reviewed', '9/17/16 10:01', 3089),
(7, 11515, 57, 'Full! Submission', '9/19/16 9:16', 3079),
(1, 11520, 19, 'Partial Submission', '8/20/16 00:42', 3078),
(1, 11520, 22, 'Junior Reviewed', '8/22/16 9:06', 3089),
(2, 11520, 28, 'Partial Submission', '8/29/16 20:12', 3078),
(2, 11520, 34, 'Junior Reviewed', '9/1/16 8:20', 3089),
(3, 11520, 38, 'Partial Submission', '9/8/16 15:03', 3078),
(4, 11520, 39, 'Partial Submission', '9/8/16 15:03', 3078),
(3, 11520, 47, 'Junior Reviewed', '9/14/16 13:53', 3089),
(5, 11520, 48, 'Full! Submission', '9/16/16 13:19', 3079),
(4, 11520, 52, 'Junior Reviewed', '9/17/16 10:51', 3089),
(6, 11520, 53, 'Full! Submission', '9/19/16 16:21', 3079)
;WITH CTE
AS
(
SELECT
*,
RowId = ROW_NUMBER() OVER (Partition BY Recordnumber ORDER BY Recordnumber, IDX),
RowIdByDescrip = ROW_NUMBER() OVER (PARTITION BY Recordnumber, DESCRIP ORDER BY Recordnumber, IDX)
FROM @tbl
)
,Test as
(
SELECT
A.Recordnumber,
A.DESCRIP,
A.EVENTNUM,
A.IDX,
A.DATES StartDate,
LEAD(A.DATES) OVER ( Partition BY A.Recordnumber ORDER BY A.IDX) EndDate,
DATEDIFF(HOUR, A.DATES, LEAD(A.DATES) OVER (Partition BY A.Recordnumber ORDER BY A.IDX)) AS DateDifff
FROM @tbl A INNER JOIN
(
SELECT
C.Recordnumber,
MIN(C.IDX) AS IDX
FROM
CTE C
GROUP BY
C.RowId - C.RowIdByDescrip,
C.DESCRIP,
C.Recordnumber
) B ON A.IDX = B.IDX and A.Recordnumber = B.Recordnumber
)
Select
*
From Test
Where eventnum in ('3078')
order by Recordnumber, IDX
答案 1 :(得分：0)
尝试如下：
DECLARE @Tbl TABLE (RowNumber INT, RecordNumber INT, IDX INT, DESCRIP NVARCHAR(50), DATES DATETIME, EVENTNUM INT)
INSERT INTO @Tbl
VALUES
(1, 11515, 13, 'Partial Submission', '8/12/16 00:21', 3078),
(1, 11515, 14, 'Junior Reviewed', '8/12/16 15:52', 3089),
(2, 11515, 26, 'Partial Submission', '8/18/16 15:24', 3078),
(3, 11515, 33, 'Partial Submission', '9/6/16 9:47', 3078),
(4, 11515, 34, 'Partial Submission', '9/6/16 9:47', 3078),
(5, 11515, 39, 'Partial Submission', '9/9/16 13:19', 3078),
(2, 11515, 40, 'Junior Reviewed', '9/11/16 8:30', 3089),
(6, 11515, 46, 'Partial Submission', '9/15/16 12:30', 3078),
(3, 11515, 54, 'Junior Reviewed', '9/17/16 10:01', 3089),
(7, 11515, 57, 'Full! Submission', '9/19/16 9:16', 3079),
(1, 11520, 19, 'Partial Submission', '8/20/16 00:42', 3078),
(1, 11520, 22, 'Junior Reviewed', '8/22/16 9:06', 3089),
(2, 11520, 28, 'Partial Submission', '8/29/16 20:12', 3078),
(2, 11520, 34, 'Junior Reviewed', '9/1/16 8:20', 3089),
(3, 11520, 38, 'Partial Submission', '9/8/16 15:03', 3078),
(4, 11520, 39, 'Partial Submission', '9/8/16 15:03', 3078),
(3, 11520, 47, 'Junior Reviewed', '9/14/16 13:53', 3089),
(5, 11520, 48, 'Full! Submission', '9/16/16 13:19', 3079),
(4, 11520, 52, 'Junior Reviewed', '9/17/16 10:51', 3089),
(6, 11520, 53, 'Full! Submission', '9/19/16 16:21', 3079)
;WITH CTE
AS
(
SELECT
*,
ROW_NUMBER() OVER (ORDER BY IDX) RowId,
ROW_NUMBER() OVER (PARTITION BY DESCRIP ORDER BY IDX) RowIdByDescrip
FROM @Tbl
WHERE
EVENTNUM IN
(
3078, --Partial Submission
3089 -- Junior Reviewed
)
), CTE2
AS
(
SELECT
MIN(C.IDX) AS IDX
FROM
CTE C
GROUP BY
C.RowId - C.RowIdByDescrip,
C.DESCRIP
)
SELECT
R.RecordNumber,
R.IDX ,
R.StartDate ,
R.EndDate ,
R.DateDifff
FROM
(
SELECT
A.EVENTNUM,
A.RecordNumber,
A.DESCRIP,
A.IDX,
A.DATES StartDate,
LEAD(A.DATES) OVER (ORDER BY A.IDX) EndDate,
DATEDIFF(HOUR, A.DATES, LEAD(A.DATES) OVER (ORDER BY A.IDX)) AS DateDifff
FROM
@Tbl A INNER JOIN
CTE2 B ON A.IDX = B.IDX
) R
WHERE
R.EVENTNUM = 3078 --Partial Submission
ORDER BY R.RecordNumber
结果：
RecordNumber IDX StartDate EndDate DateDifff
------------ ----------- ---------------- ---------------- -----------
11515 13 2016-08-12 00:21 2016-08-12 15:52 15
11515 26 2016-08-18 15:24 2016-09-06 09:47 450
11515 34 2016-09-06 09:47 2016-09-01 08:20 -121
11515 46 2016-09-15 12:30 2016-09-14 13:53 -23
11520 38 2016-09-08 15:03 2016-09-11 08:30 65
11520 19 2016-08-20 00:42 2016-08-22 09:06 57
答案 2 :(得分：0)
这不是答案。评论时间太长了。
我猜。我完全不明白这个问题。让我告诉你我所知道的。
首先，根据IDX
我只是在两个事件Partial Submission和Junior Reviewed
结果表：Partial Submission Start - Junior Reviewed END
RowNumber RecordNumber IDX DESCRIP DATES EVENTNUM RowId RowIdByDescrip
----------- ------------ ----------- -------------------------------------------------- ----------------------- ----------- -------------------- --------------------
1 11515 13 Partial Submission Start 2016-08-12 00:21:00.000 3078 1 1
1 11515 14 Junior Reviewed END 2016-08-12 15:52:00.000 3089 2 1
1 11520 19 Partial Submission Start 2016-08-20 00:42:00.000 3078 3 2
1 11520 22 Junior Reviewed END 2016-08-22 09:06:00.000 3089 4 2
2 11515 26 Partial Submission Start 2016-08-18 15:24:00.000 3078 5 3
2 11520 28 Partial Submission 2016-08-29 20:12:00.000 3078 6 4
3 11515 33 Partial Submission 2016-09-06 09:47:00.000 3078 7 5
4 11515 34 Partial Submission 2016-09-06 09:47:00.000 3078 8 6
2 11520 34 Junior Reviewed End 2016-09-01 08:20:00.000 3089 9 3
3 11520 38 Partial Submission Start 2016-09-08 15:03:00.000 3078 10 7
4 11520 39 Partial Submission 2016-09-08 15:03:00.000 3078 11 8
5 11515 39 Partial Submission 2016-09-09 13:19:00.000 3078 12 9
2 11515 40 Junior Reviewed End 2016-09-11 08:30:00.000 3089 13 4
6 11515 46 Partial Submission Start 2016-09-15 12:30:00.000 3078 14 10
3 11520 47 Junior Reviewed End 2016-09-14 13:53:00.000 3089 15 5
4 11520 52 Junior Reviewed 2016-09-17 10:51:00.000 3089 16 6
3 11515 54 Junior Reviewed 2016-09-17 10:01:00.000 3089 17 7
结果：
RecordNumber IDX StartDate EndDate DateDifff
------------ ----------- ---------------- ---------------- -----------
11515 13 2016-08-12 00:21 2016-08-12 15:52 15
11515 26 2016-08-18 15:24 2016-09-06 09:47 450
11515 34 2016-09-06 09:47 2016-09-01 08:20 -121
11515 46 2016-09-15 12:30 2016-09-14 13:53 -23
11520 38 2016-09-08 15:03 2016-09-11 08:30 65
11520 19 2016-08-20 00:42 2016-08-22 09:06 57