我的表单中有一个多文件上传控件。我试图通过下拉列表上传尽可能多的用户想要数据库的文件,以选择附件类型。我能够将文件保存到数据库,但是我的数据全部为0(0x0000000000000000000000000000000000000000 ... 00)。 当我在用户点击文件链接时尝试检索文件时,我收到一条错误,即syas"无法加载pdf文档"。
以下是我将其保存到数据库的代码:
public void getDynamicFilesFromUploadedFileList(int wWireTransferID, int wUserID)
{
if (GridView1.Rows.Count > 0)
{
foreach (GridViewRow grow in GridView1.Rows)
{
try
{
FileUpload fileuploadControl = new FileUpload();
fileuploadControl = (FileUpload)grow.FindControl("fUpControl");
DropDownList drpFileType = new DropDownList();
drpFileType = (DropDownList)grow.FindControl("ddlFileType");
Guid newID = Guid.NewGuid();
if (fileuploadControl.HasFile)
{
//I believe here is my mistake
Byte[] fileData = new Byte[fileuploadControl.PostedFile.ContentLength];
new MRSManager().InsertWTDocument(wWireTransferID,
fileuploadControl.FileName,
drpFileType.SelectedValue.Trim(),
fileuploadControl.PostedFile.ContentType,
System.IO.Path.GetExtension(fileuploadControl.FileName),
fileuploadControl.PostedFile.ContentLength.ToString(),
fileData,
wUserID,
newID);
}
else
{
string m = "No File! ";
}
}
catch (Exception Exp)
{
string msg = Exp.Message.ToString();
}
}
}
}
这是我如何尝试检索文件的代码。
protected void Page_Load(object sender, EventArgs e)
{
// Get the file id from the query string
string id = Request.QueryString["ID"];
// Get the file from the database
DataTable file = GetAFile(id);
DataRow row = file.Rows[0];
string name = (string)row["FileName"];
string contentType = (string)row["ContentType"];
Byte[] data = (Byte[])row["Data"];
Response.Clear();
Response.ClearContent();
Response.ClearHeaders();
// Send the file to the browser
Response.AddHeader("Content-type", contentType);
Response.AddHeader("Content-Disposition", "inline; filename=" + name);
Response.Buffer = true;
Response.BinaryWrite(data);
Response.Flush();
Response.Close();
Response.End();
}
// Get a file from the database by ID
public static DataTable GetAFile(string id)
{
DataTable file = new DataTable();
string sSQL = string.Format("SELECT * FROM tblWireTransferDocuments WHERE FileID = '{0}'", id);
file = SqlHelper.ExecuteDataset(DBConnection.GetConnectionString(), CommandType.Text, sSQL, null).Tables[0];
return file;
}
}
}
答案 0 :(得分:2)
你是对的
//I believe here is my mistake
Byte[] fileData = new Byte[fileuploadControl.PostedFile.ContentLength];
您只创建了fileData,但没有填充它。您应该使用fileuploadControl.FileContent来填充fileData。