Question

我有一个使用旧版python-daemon和这段代码创建的基本Python守护进程：

import time
from daemon import runner

class App():
    def __init__(self):
        self.stdin_path = '/dev/null'
        self.stdout_path = '/dev/tty'
        self.stderr_path = '/dev/tty'
        self.pidfile_path =  '/tmp/foo.pid'
        self.pidfile_timeout = 5
    def run(self):
        while True:
            print("Howdy!  Gig'em!  Whoop!")
            time.sleep(10)

app = App()
daemon_runner = runner.DaemonRunner(app)
daemon_runner.do_action()

现在一切正常但我需要向守护进程添加一个可能的命令。当前的默认命令是“start，stop，restart”。我需要第四个命令“mycommand”，它只会在执行时运行此代码：

my_function()
print "Function was successfully run!"

我尝试过谷歌搜索和研究，但无法自己解决。我尝试手动获取参数而不会陷入使用sys.argv的python-daemon代码，但无法使其正常工作。

Answer 1

查看转轮模块的代码，以下内容应该有效......我在定义stdout和stderr时遇到问题......你能测试一下吗？

from daemon import runner
import time

# Inerith from the DaemonRunner class to create a personal runner
class MyRunner(runner.DaemonRunner):

    def __init__(self, *args, **kwd):
        super().__init__(*args, **kwd)

    # define the function that execute your stuff...
    def _mycommand(self):
        print('execute my command')

    # tell to the class how to reach that function
    action_funcs = runner.DaemonRunner.action_funcs
    action_funcs['mycommand'] = _mycommand


class App():
    def __init__(self):
        self.stdin_path = '/dev/null'
        self.stdout_path = '/dev/tty'
        self.stderr_path = '/dev/tty'
        self.pidfile_path =  '/tmp/foo.pid'
        self.pidfile_timeout = 5
    def run(self):
        while True:
            print("Howdy!  Gig'em!  Whoop!")
            time.sleep(10)

app = App()
# bind to your "MyRunner" instead of the generic one
daemon_runner = MyRunner(app)
daemon_runner.do_action()

如何向python-daemon添加更多命令参数？

1 个答案: