Question

我正在努力使用原始查询的输出。我的代码如下：

cursor.execute("select f.fixturematchday, u.teamselection1or2, u.teamselectionid,u.user_id from straightred_fixture f, straightred_userselection u where u.user_id = 349 and f.fixtureid = u.fixtureid and f.fixturematchday=6 order by u.teamselection1or2")
currentSelectedTeams = cursor.fetchone()

if not currentSelectedTeams:
    currentSelectedTeam1 = 0
    currentSelectedTeam2 = 0
else:
    currentSelectedTeam1 = currentSelectedTeams[0].teamselectionid
    currentSelectedTeam2 = currentSelectedTeams[1].teamselectionid

我收到以下错误：

currentSelectedTeam1 = currentSelectedTeams[0].teamselectionid
AttributeError: 'long' object has no attribute 'teamselectionid'

任何帮助都会受到赞赏，非常感谢，Alan。

PS

如果它有助于我在MySQL中查询的结果如下：

mysql> select f.fixturematchday, u.teamselection1or2, u.teamselectionid,u.user_id from straightred_fixture f, straightred_userselection u where u.user_id = 349 and f.fixtureid = u.fixtureid and f.fixturematchday=6 order by u.teamselection1or2;
+-----------------+-------------------+-----------------+---------+
| fixturematchday | teamselection1or2 | teamselectionid | user_id |
+-----------------+-------------------+-----------------+---------+
|               6 |                 1 |              31 |     349 |
|               6 |                 2 |              21 |     349 |
+-----------------+-------------------+-----------------+---------+
2 rows in set (0.00 sec)

Answer 1

您的问题是您是using cursor.fetchone()并迭代结果，期望它返回多行。

如果您想获得前2个结果，则可能需要使用fetchmany and limit to 2 records instead。

这就是幕后发生的事情：

由于您只提取了一条记录，currentSelectedTeams[0]实际上正在返回fixturematchday列，它看起来像long类型，您无法从中访问该属性。

另一种选择是使用pretty powerful Django ORM来获取此查询结果

编辑：

如果您真的想坚持基于cursor的实施，请尝试以下方法：

cursor.execute("select f.fixturematchday, u.teamselection1or2, u.teamselectionid,u.user_id from straightred_fixture f, straightred_userselection u where u.user_id = 349 and f.fixtureid = u.fixtureid and f.fixturematchday=6 order by u.teamselection1or2 LIMIT 2")
#Note the LIMIT 2

currentSelectedTeams = cursor.fetchall()

if not currentSelectedTeams:
    currentSelectedTeam1 = 0
    currentSelectedTeam2 = 0
else:
    currentSelectedTeam1 = currentSelectedTeams[0].teamselectionid
    currentSelectedTeam2 = currentSelectedTeams[1].teamselectionid

请注意，在边缘情况下，只返回一行，此实现将失败。（您需要检查光标返回长度等。）

如果这是一个django queryset实现，它看起来像这样：

qs = Fixture.objects.filter(..).values("fixturematchday", "userselection__ teamselection1or2", "userselection__teamselectionid", "userselection__userid")[:2]

Django Raw查询用法

1 个答案: