我有下表。
Animal Vaccine_Date Vaccine
Cat 2/1/2016 y
Cat 2/1/2016 z
Dog 2/1/2016 z
Dog 1/1/2016 x
Dog 2/1/2016 y
我想得到的结果如下所示。
Animal Vaccine_Date Vaccine
Dog 1/1/2016 x
Dog 2/1/2016 y,z
Cat 2/1/2016 y,z
我有以下代码,是通过我在“Combine(concatenate) rows based on dates via SQL”
的其他帖子提供的WITH RECURSIVE recCTE AS
(
SELECT
animal,
vaccine_date,
CAST(min(vaccine) as VARCHAR(50)) as vaccine, --big enough to hold concatenated list
cast (1 as int) as depth --used to determine the largest/last group_concate (the full group) in the final select
FROM TableOne
GROUP BY 1,2
UNION ALL
SELECT
recCTE.animal,
recCTE.vaccine_date,
trim(trim(recCTE.vaccine)|| ',' ||trim(TableOne.vaccine)) as vaccine,
recCTE.depth + cast(1 as int) as depth
FROM recCTE
INNER JOIN TableOne ON
recCTE.animal = TableOne.animal AND
recCTE.vaccine_date = TableOne.vaccine_date and
TableOne.vaccine > recCTE.vaccine
WHERE recCTE.depth < 5
)
--Now select the result with the largest depth for each animal/vaccine_date combo
SELECT * FROM recCTE
QUALIFY ROW_NUMBER() OVER (PARTITION BY animal,vaccine_date ORDER BY depth desc) =1
但这导致以下结果。
Animal Vaccine_Date vaccine depth
Cat 2/1/2016 y,z,z,z,z 5
Dog 1/1/2016 x 1
Dog 2/1/2016 y,z,z,z,z 5
“z”不断重复。这是因为代码说的是比最小疫苗更大的代码。为了解释这一点,代码已更改为以下内容。
WITH RECURSIVE recCTE AS
(
SELECT
animal,
vaccine_date,
CAST(min(vaccine) as VARCHAR(50)) as vaccine, --big enough to hold concatenated list
cast (1 as int) as depth, --used to determine the largest/last group_concate (the full group) in the final select
vaccine as vaccine_check
FROM TableOne
GROUP BY 1,2,5
UNION ALL
SELECT
recCTE.animal,
recCTE.vaccine_date,
trim(trim(recCTE.vaccine)|| ',' ||trim(TableOne.vaccine)) as vaccine,
recCTE.depth + cast(1 as int) as depth,
TableOne.vaccine as vaccine_check
FROM recCTE
INNER JOIN TableOne ON
recCTE.animal = TableOne.animal AND
recCTE.vaccine_date = TableOne.vaccine_date and
TableOne.vaccine > recCTE.vaccine and
vaccine_check <> recCTE.vaccine_check
WHERE recCTE.depth < 5
)
--Now select the result with the largest depth for each animal/vaccine_date combo
SELECT * FROM recCTE
QUALIFY ROW_NUMBER() OVER (PARTITION BY animal,vaccine_date ORDER BY depth desc) =1
然而,这导致以下结果。
Animal Vaccine_Date vaccine depth vaccine_check
Cat 2/1/2016 y 1 y
Dog 1/1/2016 x 1 x
Dog 2/1/2016 y 1 y
代码中缺少什么来获得以下所需的结果。
Animal Vaccine_Date Vaccine
Dog 1/1/2016 x
Dog 2/1/2016 y,z
Cat 2/1/2016 y,z
答案 0 :(得分:0)
嗯。我手边没有Teradata,但这是该项目的一个主要缺点(在我看来)。我认为这对你有用,但可能需要一些调整:
with tt as (
select t.*,
row_number() over (partition by animal, vaccine_date order by animal) as seqnum
count(*) over (partition by animal, vaccine_date) as cnt
),
recursive cte as (
select animal, vaccine_date, vaccine as vaccines, seqnum, cnt
from tt
where seqnum = 1
union all
select cte.animal, cte.dte, cte.vaccines || ',' || t.vaccine, tt.seqnum, tt.cnt
from cte join
tt
on tt.animal = cte.animal and
tt.vaccine_date = cte.vaccine_date and
tt.seqnum = cte.seqnum + 1
)
select cte.*
from cte
where seqnum = cnt;
答案 1 :(得分:0)
如果您的Teradata Database版本是14.10或更高版本,则它支持XML数据类型。这也意味着支持XMLAGG
函数,这对您的情况很有用,可以避免递归。
检查是否存在XMLAGG
函数,该函数随XML服务一起安装为UDF:
SELECT * FROM dbc.FunctionsV WHERE FunctionName = 'XMLAGG'
如果是,则查询如下:
SELECT
animal,
vaccine_date
TRIM(TRAILING ',' FROM CAST(XMLAGG(vaccine || ',' ORDER BY vaccine) AS VARCHAR(10000)))
FROM
tableone
GROUP BY 1,2
我无法测试此atm,但我相信这应该可以进行小调整。
答案 2 :(得分:0)
我能够使用以下SQL获得所需的结果。这看起来效率不高,并不是动态的。但是,我可以根据需要添加额外的子查询,以便按动物按日期组合更多的疫苗。
select
qrya.animal
,qrya.vaccine_date
,case when qrya.vac1 is not null then qrya.vac1 else null end ||','||case when qrya.animal=qryb.animal and qrya.vaccine_date=qryb.vaccine_date then qryb.Vac2 else 'End' end as vaccine_List
from
(
select
qry1.Animal
,qry1.Vaccine_Date
,case when qry1.Vaccine_Rank = 1 then qry1.vaccine end as Vac1
from
(
select
animal
,vaccine_date
,vaccine
,row_number() over (partition by animal,vaccine_date order by vaccine) as Vaccine_Rank
from TableOne
) as qry1
where vac1 is not null
group by qry1.Animal,
qry1.Vaccine_Date
,case when qry1.Vaccine_Rank = 1 then qry1.vaccine end
) as qrya
join
(
select
qry1.Animal
,qry1.Vaccine_Date
,case when qry1.Vaccine_Rank = 2 then qry1.vaccine end as Vac2
from
(
select
animal
,vaccine_date
,vaccine
,row_number() over (partition by animal,vaccine_date order by vaccine) as Vaccine_Rank
from TableOne
) as qry1
where vac2 is not null
group by qry1.Animal,
qry1.Vaccine_Date
,case when qry1.Vaccine_Rank = 2 then qry1.vaccine end
) as qryb
on qrya.Animal=qryb.Animal