使用ListView时,我可以通过编写this.adapter.delete(mYeets.get(position))
轻松删除适配器中的项目。使用RecyclerView,是否有相同的功能?或者通知适配器我现在要做的所有改变?
private void deleteComment(int position) {
String currentUserObjectId = ParseUser.getCurrentUser().getObjectId();
ParseQuery<ParseObject> query = new ParseQuery<>("Yeet");
query.whereEqualTo(ParseConstants.KEY_OBJECT_ID, mYeets.get(position).getObjectId());
query.whereContains(ParseConstants.KEY_SENDER_ID, currentUserObjectId);
query.findInBackground((yeet, e) -> {
if (e == null) {
for (ParseObject yeetObject : yeet) {
if (yeetObject.getParseObject(ParseConstants.KEY_SENDER_AUTHOR_POINTER).getObjectId().equals((ParseUser.getCurrentUser().getObjectId()))) {
AlertDialog.Builder dialogBuilder = new AlertDialog.Builder(mContext);
dialogBuilder.setTitle("Delete");
dialogBuilder.setMessage("Do you want to delete this Yeet?");
dialogBuilder.setPositiveButton("Yes", (dialog, which) -> {
// Iterate over all messages and delete them
for (ParseObject delete : yeet) {
delete.deleteInBackground();
//this.adapter.delete(mYeets.get(position));
this.adapter.notifyDataSetChanged();
Toast.makeText(mContext, "Yeet deleted", Toast.LENGTH_SHORT).show();
}
});
dialogBuilder.setNegativeButton("No", (dialog, which) -> {
});
AlertDialog alertDialog = dialogBuilder.create();
alertDialog.show();
}
}
} else {
Log.e("Error", e.getMessage());
}
});
}
答案 0 :(得分:3)
如果您正在使用RecyclerView,只需从列表中删除该项目并调用方法notifiyDataSetChanged;
答案 1 :(得分:1)
只需从RecyclerView.Adapter使用的数据结构(List)中删除该项,然后调用其notifyItemRemoved()应该是最好的方法。
之前建议的notifyDataSetChanged()会不必要地使列表中的每个项目无效,而不仅仅是位于已删除项目之后的项目。