$sql= "
SELECT tbl_doctors. * ,
tbl_specialisation. * ,
tbl_doctor_address.addr_id,
tbl_address . *
FROM `tbl_doctors` INNER JOIN
`tbl_specialisation`
ON ( tbl_doctors.dr_spec_id = tbl_specialisation.spec_id ) INNER JOIN
(tbl_doctor_address JOIN
tbl_address
ON tbl_doctor_address.addr_id = tbl_address.addr_id
)
ON tbl_doctors.dr_id = tbl_doctor_address.dr_id
WHERE tbl_doctors.dr_id = '$id'";
答案 0 :(得分:0)
我想这部分需要改造:
(tbl_doctor_address JOIN
tbl_address
ON tbl_doctor_address.addr_id = tbl_address.addr_id
)
ON tbl_doctors.dr_id = tbl_doctor_address.dr_id
就像这样:
INNER JOIN `tbl_doctor_address` ON tbl_doctors.dr_id = tbl_doctor_address.dr_id
INNER JOIN `tbl_address` ON tbl_doctor_address.addr_id = tbl_address.addr_id
如果没有为医生设置地址,您可以使用LEFT JOIN
:
LEFT JOIN `tbl_doctor_address` ON tbl_doctors.dr_id = tbl_doctor_address.dr_id
LEFT JOIN `tbl_address` ON tbl_doctor_address.addr_id = tbl_address.addr_id
告诉我它是否有帮助?