为什么.txt文件输出中的每一行都以' System.int32'?结尾? C#

时间:2016-09-19 09:11:27

标签: c# streamwriter int32

  

C#,   控制台应用,   Virtual Studio 2015,   Paralelles:Windows 8.1。

代码如下:

class txt_program
{
    public void txt()
    {
        /* 0 */
        int[] M_array_0 = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 };
        /* 1 */
        int[] M_array_1 = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 };
        /* 2 */
        int[] M_array_2 = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 };
        // etc.

        // the M matrix
        int[][] M = { M_array_0, M_array_1, M_array_2, M_array_3, M_array_4,
        M_array_5, M_array_6, M_array_7, M_array_8, M_array_9, M_array_10,
        M_array_12, M_array_13 };

        // the time pick is beeing called into this item.
        Time_pick_2 T2 = new Time_pick_2();

        // the if loop making

        // 0
        if (T2.M_build_0() == true)
        {
            int nr_0 = 0;
            for (int i = nr_0; i < nr_0 + 2; i++)
            {
                M[1][i] = M_array_0[i] + 1;
            }
        }

        // 1
        else if (T2.M_build_1() == true)
        {
            int nr_1 = 1;
            for (int i = nr_1; i < nr_1 + 2; i++)
            {
                M[1][i] = M_array_1[i] + 1;
            }
        }

        // 2
        else if (T2.M_build_2() == true)
        {
            int nr_2 = 2;
            for (int i = nr_2; i < nr_2 + 2; i++)
            {
                M[2][i] = M_array_2[i] + 1;

            }
        }

        // etc.



        using (StreamWriter SW = new StreamWriter(@"txt.txt"))
            {
                // the loops creating the .txt-file.
                for (int i = 0; i < M.GetLength(0); i++)
                {
                    for (int a = 0; a < 13; a++)
                    {
                        SW.Write(" " + M[i][a]);
                    }
                    SW.WriteLine(M);
                }
            }
        }
    }
}

作为pastebin:

http://pastebin.com/3HDYwzzZ

输出为:

0 0 0 0 0 0 0 0 0 0 0 0 0System.Int32[][]
0 1 1 0 0 0 0 0 0 0 0 0 0System.Int32[][]
0 0 0 0 0 0 0 0 0 0 0 0 0System.Int32[][]
// etc.

我查看了关于System.Int32[][]外观的其他帖子,但在所有情况下,代码除了System.Int32[]之外没有生成任何输出,这意味着代码无法解释{{1创建输出。此处显示正确的输出,但仍显示for-loop结尾。为什么这样,我做错了什么?

3 个答案:

答案 0 :(得分:0)

您在内循环后输出整个数组。如果您想要换行,可以使用Console.WriteLine("")

using (StreamWriter SW = new StreamWriter(@"txt.txt"))
{
    // the loops creating the .txt-file.
    for (int i = 0; i < M.GetLength(0); i++)
    {
        for (int a = 0; a < 13; a++)
        {
            SW.Write(" " + M[i][a]);
        }
        //SW.WriteLine(M); // <-- this line was generating your output
        SW.WriteLine("");
    }
}

答案 1 :(得分:0)

默认情况下,ToString方法返回对象的类型。因此,如果在不重写ToString方法(在Object类中定义)的情况下打印非基本类型,则会获得类型名称。

您的案例中的问题是:

SW.WriteLine(M);

答案 2 :(得分:0)

正如Heinzbeinz已经说过要打印一个在C#中导致打印对象类型的数组,例如:

int[] ar1 = {0,1,2,3};
int[] ar2 = {0,1,2,3};
int[][] m = {ar1,ar2};

Console.WriteLine(m);

将导致打印System.Int32 [] []