C#, 控制台应用, Virtual Studio 2015, Paralelles:Windows 8.1。
代码如下:
class txt_program
{
public void txt()
{
/* 0 */
int[] M_array_0 = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 };
/* 1 */
int[] M_array_1 = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 };
/* 2 */
int[] M_array_2 = { 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 };
// etc.
// the M matrix
int[][] M = { M_array_0, M_array_1, M_array_2, M_array_3, M_array_4,
M_array_5, M_array_6, M_array_7, M_array_8, M_array_9, M_array_10,
M_array_12, M_array_13 };
// the time pick is beeing called into this item.
Time_pick_2 T2 = new Time_pick_2();
// the if loop making
// 0
if (T2.M_build_0() == true)
{
int nr_0 = 0;
for (int i = nr_0; i < nr_0 + 2; i++)
{
M[1][i] = M_array_0[i] + 1;
}
}
// 1
else if (T2.M_build_1() == true)
{
int nr_1 = 1;
for (int i = nr_1; i < nr_1 + 2; i++)
{
M[1][i] = M_array_1[i] + 1;
}
}
// 2
else if (T2.M_build_2() == true)
{
int nr_2 = 2;
for (int i = nr_2; i < nr_2 + 2; i++)
{
M[2][i] = M_array_2[i] + 1;
}
}
// etc.
using (StreamWriter SW = new StreamWriter(@"txt.txt"))
{
// the loops creating the .txt-file.
for (int i = 0; i < M.GetLength(0); i++)
{
for (int a = 0; a < 13; a++)
{
SW.Write(" " + M[i][a]);
}
SW.WriteLine(M);
}
}
}
}
}
作为pastebin:
输出为:
0 0 0 0 0 0 0 0 0 0 0 0 0System.Int32[][]
0 1 1 0 0 0 0 0 0 0 0 0 0System.Int32[][]
0 0 0 0 0 0 0 0 0 0 0 0 0System.Int32[][]
// etc.
我查看了关于System.Int32[][]
外观的其他帖子,但在所有情况下,代码除了System.Int32[]
之外没有生成任何输出,这意味着代码无法解释{{1创建输出。此处显示正确的输出,但仍显示for-loop
结尾。为什么这样,我做错了什么?
答案 0 :(得分:0)
您在内循环后输出整个数组。如果您想要换行,可以使用Console.WriteLine("")
using (StreamWriter SW = new StreamWriter(@"txt.txt"))
{
// the loops creating the .txt-file.
for (int i = 0; i < M.GetLength(0); i++)
{
for (int a = 0; a < 13; a++)
{
SW.Write(" " + M[i][a]);
}
//SW.WriteLine(M); // <-- this line was generating your output
SW.WriteLine("");
}
}
答案 1 :(得分:0)
默认情况下,ToString方法返回对象的类型。因此,如果在不重写ToString方法(在Object类中定义)的情况下打印非基本类型,则会获得类型名称。
您的案例中的问题是:
SW.WriteLine(M);
答案 2 :(得分:0)
正如Heinzbeinz已经说过要打印一个在C#中导致打印对象类型的数组,例如:
int[] ar1 = {0,1,2,3};
int[] ar2 = {0,1,2,3};
int[][] m = {ar1,ar2};
Console.WriteLine(m);
将导致打印System.Int32 [] []