我试图使用json创建一个从属下拉列表框。例如:如果选择的汽车品牌是“bmw”,那么汽车模型下拉列表必须只显示列表中的“suv”,其他两个选项不应该不显示。对于“梅赛德斯”,它应该只显示汽车模型中的“suv”和“coupe”。还请解释一下json的用途是什么?以及它如何影响代码。
my.html
Car Brand:
<select name="carname" ng-model="userSelect" required>
<option value="">--Select--</option>
<span ng-show="valdate.carname.$error.required">Car name</span>
<option ng-repeat="ManufactureBrand in a" ng-bind="ManufactureBrand" >
{{ManufactureBrand}}
</option>
</select>
<br/>
<br/> Car Model:
<select name="carmodel" ng-model="selectCar" required>
<option value="">--Select--</option>
<span ng-show="valdate.carmodel.$error.required">Car name</span>
<option ng-repeat="CarName in b" ng-bind="CarName">
{{CarName}}
</option>
</select>
<br/>
<input type="submit" ng-click="checkselection()" ng-disabled="valdate.carname.$invalid && valdate.carmodel.$invalid">
的script.js
app.factory('Brandtest', function () {
var brand = {};
brand.sample = ['Bmw', 'Mercedes', 'Honda'];
brand.car = ['Suv', 'Sedan', 'Cope'];
{
return brand;
}
});
app.controller('selectDropdown', ['$scope', 'Brandtest', function ($scope, Brandtest) {
$scope.a = Brandtest.sample;
$scope.b = Brandtest.car;
$scope.list=[];
$scope.carlist=[];
$scope.checkselection = function () {
if ($scope.userSelect != "" && $scope.userSelect != undefined &&
$scope.selectCar != "" && $scope.selectCar != undefined )
{
$scope.list.push($scope.userSelect);
$scope.carlist.push($scope.selectCar);
}
提前致谢。
答案 0 :(得分:0)
你必须在2个下拉列表之间保持一些共同关系。最好是拥有一个json对象,并使用ng-options根据第一个下拉列表中选择的值填充第二个下拉列表。运行下面的演示程序,你就明白了。
<!DOCTYPE html>
<html>
<script src="http://ajax.googleapis.com/ajax/libs/angularjs/1.4.8/angular.min.js"></script>
<body>
<div ng-app="myApp" ng-controller="myCtrl">
<h1>Select a car:</h1>
<select ng-model="x" ng-options="x for (x, y) in cars"></select>
<h1 ng-if="x">Category: </h1>
<select ng-if="x" ng-model="y" ng-options="y for y in x"></select>
</div>
<script>
var app = angular.module('myApp', []);
app.controller('myCtrl', function($scope) {
$scope.cars = {
"car01" : ["Ford", "BMW", "NISSAN"],
"car02" : ["Fiat", "Infinity"],
"car03" : ["Volvo", "Toyota"]
}
});
</script>
</body>
</html>
答案 1 :(得分:0)
这是工作plunkr
您必须修改以下代码
你的工厂应该是这样的
app.factory('Brandtest', function () {
var brand = {};
brand.sample =[
{
"id": 0,
"carName": "BMW"
},
{
"id": 1,
"carName": "Mercedes"
},
{
"id": 2,
"carName": "Honda"
}
];
brand.car =[
{
"id": 0,
"carType": "Suv",
"parentId": 0
},
{
"id": 1,
"carType": "Sedan",
"parentId": 1
},
{
"id": 2,
"carType": "Cope",
"parentId": 2
}
];
{
return brand;
}
});
在您的HTML中修改如下代码
<body ng-controller="selectDropdown">
Car Brand:
<select name="carname" ng-model="userSelect" ng-options="p.carName for p in a" required>
<option value="">--Select--</option>
<span ng-show="valdate.carname.$error.required">Car name</span>
</select>
<br/>
<br/> Car Model:
<select name="carmodel" ng-model="selectCar" ng-options="c.carType for c in b | filter:{parentId: userSelect.id}" required>
<option value="">--Select--</option>
<span ng-show="valdate.carmodel.$error.required">Car name</span>
</select>
<br/>
<input type="submit" ng-click="checkselection()" ng-disabled="valdate.carname.$invalid && valdate.carmodel.$invalid">
<table>
<tr>
<th>Car Name</th>
<th>Car Model</th></tr>
<tr ng-repeat="carz in list track by $index">
<td>{{carz.carName}}</td>
<td>{{carlist[$index].carType}}</td>
</tr>
</table>
</body>