我创建了一个生成并返回字母和数字的随机字符串的方法,但由于某种原因,我只得到一个带数字的字符串,字符串的长度不接近我要求的字符串是。返回的一些字符串示例:“478388299949939566”(插入18作为长度),“3772919388584334”(插入9作为长度),“2293010089409293945”(插入6作为长度)。任何人都能看到我在这里缺少的东西吗?
func generateRandomStringWithLength(length:Int) -> String {
let randomString:NSMutableString = NSMutableString(capacity: length)
let letters:NSMutableString = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
for index in 0...length {
let randomIndex:Int = Int(arc4random_uniform(UInt32(62)))
randomString.append("\(letters.character(at: randomIndex))")
}
return String(randomString)
}
答案 0 :(得分:3)
你的问题在这里:
letters.character(at: randomIndex)
它的函数返回给定UTF-16代码单元索引处的字符,而不仅仅是字符
这是我的版本,我想它更快。
func generateRandomStringWithLength(length: Int) -> String {
var randomString = ""
let letters = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
for _ in 1...length {
let randomIndex = Int(arc4random_uniform(UInt32(letters.characters.count)))
let a = letters.index(letters.startIndex, offsetBy: randomIndex)
randomString += String(letters[a])
}
return randomString
}
generateRandomStringWithLength(length: 5)
答案 1 :(得分:1)
使用此:
func generateRandomStringWithLength(length:Int) -> String {
let randomString:NSMutableString = NSMutableString(capacity: length)
let letters:NSMutableString = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
var i: Int = 0
while i < length {
let randomIndex:Int = Int(arc4random_uniform(UInt32(letters.length)))
randomString.appendString("\(Character( UnicodeScalar( letters.characterAtIndex(randomIndex))))")
i += 1
}
return String(randomString)
}
print(generateRandomStringWithLength(5))
print(generateRandomStringWithLength(10))
print(generateRandomStringWithLength(20))
print(generateRandomStringWithLength(7))
print(generateRandomStringWithLength(14))
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