如何使用改造同时发送图像和文本

时间:2016-09-18 14:16:32

标签: android retrofit okhttp

我想使用改造同时发送此Postdata和imagefile。

PostData

public class PostData implements Serializable {
    @Expose
    private String text;
    @Expose
    private Point point;
}
public class Point implements Serializable {
    @Expose
    private double longitude;
    @Expose
    private double latitude;
}

PostApiService

public interface PostApiService {

    @Multipart
    @POST("posts/")
    Call<ResponseBody> uploadFile (@Part MultipartBody.Part part, @Body PostData postData);
}

我从这些代码中获取图像uri,我将使用它。它用作returnUri。 你可以考虑这个。

代码:

view.findViewById(R.id.btn_post).setOnClickListener(new View.OnClickListener() {
    @Override
    public void PostImageAndData(View view) {

        Bitmap bitmap = null;
        try {
            bitmap = getBitmapFromUri(returnUri); #this method is to make Bitmap from Uri
        } catch (IOException e) {
            e.printStackTrace();
        }
        File imageFile = null;
        try {
            imageFile = createFileFromBitmap(bitmap); #this method is to make File from Bitmap
        } catch (IOException e) {
            e.printStackTrace();
        }

        OkHttpClient client = new OkHttpClient();
        OkHttpClient.Builder builder = new OkHttpClient.Builder();
        client = builder.build();
        Retrofit retrofit = new Retrofit.Builder()
                .client(client)
                .addConverterFactory(GsonConverterFactory.create())
                .baseUrl(Constants.HTTP.BASE_URL)
                .build();

        PostApiService postApiService = retrofit.create(PostApiService.class);
        RequestBody requestFile =
                RequestBody.create(MediaType.parse("multipart/form-data"), imageFile);
        MultipartBody.Part body =
                MultipartBody.Part.createFormData("image", makeImageFileName(), requestFile); #this method(makeimageFileName()) is for custom filename 
        Point mpoint = new Point(13, 15);
        PostData postData = new PostData("hello", mpoint);

        Call<ResponseBody> call = postApiService.uploadFile(body, postData);
        call.enqueue(new Callback<ResponseBody>() {
            @Override
            public void onResponse(Call<ResponseBody> call, Response<ResponseBody> response) {
                Toast.makeText(getContext(), "success?", Toast.LENGTH_LONG).show();
            }
            @Override
            public void onFailure(Call<ResponseBody> call, Throwable t) {
            }
        });
    }
});

如果我在PostApiService上使用@Body PostData postData,则错误为java.lang.IllegalArgumentException: @Body parameters cannot be used with form or multi-part encoding. (parameter #2)

如果我在PostApiService上使用@Part PostData postData,则错误为java.lang.IllegalArgumentException: @Part annotation must supply a name or use MultipartBody.Part parameter type. (parameter #2)

那么,我该怎么办?

拜托,你能帮助我吗?

1 个答案:

答案 0 :(得分:2)

昨天我遇到了同样的问题,我已经解决了。

它直接说不允许两种不同的格式。 java.lang.IllegalArgumentException:@Body参数不能与表单或多部分编码一起使用。 (参数#2)

您需要仅以部分的形式发送所有数据。

@Multipart
@POST("/api/Accounts/editaccount")
Call<User> editUser (@Part("Authorization") String authorization,@Part("file\"; filename=\"pp.png\" ") RequestBody file , @Part("FirstName") RequestBody fname, @Part("Id") RequestBody id);

像这样。

谢谢希望这对你有所帮助。