如果目标是让'result'代表'results'数组中的一个对象,那么为什么不将case let
放在下面,而只是'for result in'?我不明白为什么这里需要case let
。
if let data = data, let json = try? JSONSerialization.jsonObject(with: data, options: []) as? [String: Any] {
for case let result in json["results"] {
if let restaurant = Restaurant(json: result) {
restaurants.append(restaurant)
}
}
}
JSON
{
"query": "sandwich",
"results_count": 12,
"page": 1,
"results": [
{
"name": "Caffè Macs",
"coordinates": {
"lat": 37.330576,
"lng": -122.029739
},
"meals": ["breakfast", "lunch", "dinner"]
},
...
]
}
答案 0 :(得分:10)
在您的情况下,不需要将case let
与for循环一起使用,因为您希望results
响应的所有对象,如果您想了解case let
的使用方法,请检查此项。
let albumDic = [
("Red", 2014),
("1989", 2014),
("Fearless", 2008),
("Speak Now", 2008)
]
for case let (album, 2014) in albumDic {
print("Album \(album) was released in 2014")
}
<强>输出强>
Album Red was released in 2014
Album 1989 was released in 2014
注意:您可以直接使用for循环,因为您需要所有对象,因此无需使用case let
。所以您需要这样写。
if let results = json["results"] as? [[String: Any]]{
for result in results {
}
}
有关详细信息,请查看此tutorial for for。