Question

我使用了多个if ifif，也有重复尝试，如果，除了命令消除负，非整数，非数字输入，我可以有一个命令，完全消除那些？谢谢！代码如下：

print("Welcome to Supermarket")
print("1. Potatoes($0.75 per potato)")
print("2. Tomatoes ($1.25 per tomato)")
print("3. Apples ($0.50 per apple)")
print("4. Mangoes ($1.75 per mango)")
print("5. checkout")

total = 0
i = 0
while i <= 0:
    try:
        choice = int(input("please enter 1, 2, 3, 4 or 5: "))
        if choice not in (1, 2, 3, 4, 5):
            raise ValueError()
    except ValueError:
        print("invalid input, you need to enter 1, 2, 3, 4 or5")
        choice = -1
    else:
        if choice == 1:
            try:
                amount = int(input("how many potatoes do you want? "))
                if amount < 0:
                    raise ValueError()
            except ValueError:
                print("invalid input")
            else:
                total = 0.75 * amount + total
                cop = 0.75 * amount
                print("the cost of potatoes is $", format(cop, ".2f"))
                print("the total now is $", format(total, ".2f"))
        elif choice == 2:
            try:
                amount = int(input("how many tomatoes do you want? "))
                if amount < 0:
                    raise ValueError()
            except ValueError:
                print("invalid input")
            else:
                total = 1.25 * amount + total
                cot = 1.25 * amount
                print("the cost of tomatoes is $", format(cot, ".2f"))
                print("the total now is $", format(total, ".2f"))
        elif choice == 3:
            try:
                amount = int(input("how many apples do you want? "))
                if amount < 0:
                    raise ValueError()
            except ValueError:
                print("invalid input")
            else:
                total = 0.5 * amount + total
                coa = 0.5 * amount
                print("the cost of apples is $", format(coa, ".2f"))
                print("the total now is $", format(total, ".2f"))
        elif choice == 4:
            try:
                amount = int(input("how many mangoes do you want? "))
                if amount < 0:
                    raise ValueError()
            except ValueError:
                print("invalid input")
            else:
                total = 1.75 * amount + total
                com = 1.75 * amount
                print("the cost of mangoes is $", format(com, ".2f"))
                print("the total now is $", format(total, ".2f"))
        elif choice == 5:
            print("your total is $", format(total, ".2f"))
            choice = choice + 1
        i = choice - 5

k = 0
while k < 1:
    try:
        insert = float(
            input("enter you payment to the nearest cent(ex. 17.50 means you have entered 17 dollars and 50 cents): "))
        if (insert - total) < 0:
            raise ValueError()
    except ValueError:
        print(
            "you must enter a number in the form like '17.50' and you have to enter an amount more than the total cost!")
        k = k - 1
    else:
        change = insert - total
        five_do = int(change / 5)
        one_do = int(change % 5)
        quart = int((change - five_do * 5 - one_do) / 0.25)
        dime = int((change - five_do * 5 - one_do - quart * 0.25) / 0.1)
        nickel = int((change - five_do * 5 - one_do - quart * 0.25 - dime * 0.1) / 0.05)
        penny = (change - five_do * 5 - one_do - quart * 0.25 - dime * 0.1 - nickel * 0.05) * 100
        print("total change is: $ ", format(change, ".2f"))
        print("give customer: ", five_do, "$5 note,", one_do, "$1 note,",
              quart, "quartz,", dime, "dimes,", nickel, "nickels,", format(penny, ".0f"), "pennies")

Answer 1

将常用验证码提取到它自己的函数中：

def validate_input(input_message):
    """Validate that input is a positive integer"""
    amount = int(input(input_message))
    if amount < 0:
        raise ValueError("positive number required")
    return amount

然后根据需要调用该函数：

if choice == 1:
    try:
        amount = validate_input("how many potatoes do you want? ")
    except ValueError:
        # do something with invalid input here
    else:
        # do something with valid input here

当你在代码中有这种重复时，看看是否有办法将它重构为函数是值得的。

Answer 2

我建议做一个验证输入是整数且大于零的函数。类似的东西：

def validateInt(value):
    value = int(value)   #try to cast the value as an integer

    if value < 0:
        raise ValueError

在您的代码中，您现在可以按如下方式使用它：

choice = input("Choose an option : ")
try:
    validateInt(choice)
except:
    Print("Invalid Input.")

如果除了python中的代码用于重复输入，如何简化尝试？

2 个答案: