Question

我有一个有趣的问题实际上让我感到非常悲伤。

我有2张化妆相同的桌子。一张桌子持有给定抽奖的中奖彩票号码，另一张桌子持有500张随机生成的＃34;门票＆＃34;那次抽奖。

我正在尝试编写一些代码，告诉我500张门票中有多少有3个匹配的号码，4个匹配的号码，5个匹配的号码，当然还有6个匹配的号码。

两个表的表结构是

id，playDate，num1，num2，num3，num4，num5，num6。

这是我所处的地方，我知道在任何人说什么之前这是不正确的。真的在这里挣扎：

SELECT count(*) AS c, w.*, l.* 
FROM winningNums AS w, lottoNums AS l
WHERE w.playDate = "2016-10-10"
AND l.playDate = "2016-10-10"
AND l.num1 (
w.num1, w.num2, w.num3, w.num4, w.num5, w.num6 
)

我也在打击这样的事情

SELECT * 
FROM winningNums AS w
INNER JOIN lottoNums AS l
ON w.playDate = l.playDate
AND w.num1 = l.num1
AND w.num2 = l.num2
AND w.num3 = l.num3
AND w.num4 = l.num4
AND w.num5 = l.num5
AND w.num6 = l.num6

我面临的主要问题是3场比赛的胜利可能来自num1，num3和num4（来自票证），与num2，num5和num6（来自中奖号码）相匹配。

帮助： - ）

Answer 1

SELECT l.*,
    (l.num1 IN (w.num1, w.num2, w.num3, w.num4, w.num5, w.num6)) +
    (l.num2 IN (w.num1, w.num2, w.num3, w.num4, w.num5, w.num6)) +
    (l.num3 IN (w.num1, w.num2, w.num3, w.num4, w.num5, w.num6)) +
    (l.num4 IN (w.num1, w.num2, w.num3, w.num4, w.num5, w.num6)) +
    (l.num5 IN (w.num1, w.num2, w.num3, w.num4, w.num5, w.num6)) +
    (l.num6 IN (w.num1, w.num2, w.num3, w.num4, w.num5, w.num6))
    AS hits
FROM winningNums AS w
CROSS JOIN lottoNums AS l
WHERE w.playDate = "2016-10-10"
  AND l.playDate = "2016-10-10"
HAVING hits >= 3
ORDER BY hits DESC

这会将票证中的每个号码与彩票中的每个号码进行比较。并且将添加所有匹配/匹配。

Answer 2

您可以使用IN语句查找返回1或0的匹配项，然后将它们添加到计数匹配项数... 然后使用HAVING检查匹配＆gt; = 3这样。

SELECT lot.id as lotid,draw.id as drawid,
     (draw.num1 IN (lot.num1,lot.num2,lot.num3,lot.num4,lot.num5,lot.num6))
   + (draw.num2 IN (lot.num1,lot.num2,lot.num3,lot.num4,lot.num5,lot.num6))
   + (draw.num3 IN (lot.num1,lot.num2,lot.num3,lot.num4,lot.num5,lot.num6))
   + (draw.num4 IN (lot.num1,lot.num2,lot.num3,lot.num4,lot.num5,lot.num6))
   + (draw.num5 IN (lot.num1,lot.num2,lot.num3,lot.num4,lot.num5,lot.num6))
   + (draw.num6 IN (lot.num1,lot.num2,lot.num3,lot.num4,lot.num5,lot.num6))
   AS matches
FROM lot
  INNER JOIN draw
HAVING matches >= 3;

sqlfiddle

将数百行数据与另一个表中的数据进行比较

2 个答案: