Question

我有一张这样的表：

Id    Date     Price  Item  Type
1  2009-09-21    25     1     M
2  2009-08-31    16     2     T
1  2009-09-23    21     1     M
2  2009-09-03    12     3     T

我尝试接收type ='M'的ID和和价格多列项的列的输出以及type ='T'的具有相同逻辑的另一列

如何为我做这件事的唯一方法是使用multi-cte但它有点复杂和大：

with cte as (
select distinct a.id, a.date
sum(price*a.item) as numm
from table a
where a.type='M'
group by a.id), 

crx as (
select cte.id, cte.numm, sum(a.price*a.item) as numm_1  from cte
join table a on a.id=cte.id and a.date=cte.date
where a.type='T'
group by cte.id)

select * from crx

有一定的感觉，可以做得更好（例如使用子查询） - 询问你怎么做。

P.S。

非常感谢SQLlite的东西！

谢谢！

Answer 1

也许这会有所帮助

Declare @YourTable table (Id int,Date date,Price money,Item int,Type varchar(25))
Insert into @YourTable values
(1,'2009-09-21',25,1,'M'),
(2,'2009-08-31',16,2,'T'),
(1,'2009-09-23',21,1,'M'),
(2,'2009-09-03',12,3,'T')

Select ID
      ,sum(case when Type='M' then Price*Item else 0 end) as M
      ,sum(case when Type='T' then Price*Item else 0 end) as T
 From  YourTable
 Group By ID

返回

ID  M       T
1   46.00   0.00
2   0.00    68.00

sql

1 个答案: