{
"results" : [
{
"address_components" : [
{
"long_name" : "1600",
"short_name" : "1600",
"types" : [ "street_number" ]
},
{
"long_name" : "Amphitheatre Parkway",
"short_name" : "Amphitheatre Pkwy",
"types" : [ "route" ]
},
{
"long_name" : "Mountain View",
"short_name" : "Mountain View",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Santa Clara County",
"short_name" : "Santa Clara County",
"types" : [ "administrative_area_level_2", "political" ]
},
{
"long_name" : "California",
"short_name" : "CA",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "United States",
"short_name" : "US",
"types" : [ "country", "political" ]
},
{
"long_name" : "94043",
"short_name" : "94043",
"types" : [ "postal_code" ]
}
],
"formatted_address" : "1600 Amphitheatre Pkwy, Mountain View, CA 94043, USA",
"geometry" : {
"location" : {
"lat" : 37.4224484,
"lng" : -122.0843249
},
"location_type" : "ROOFTOP",
"viewport" : {
"northeast" : {
"lat" : 37.4237973802915,
"lng" : -122.0829759197085
},
"southwest" : {
"lat" : 37.4210994197085,
"lng" : -122.0856738802915
}
}
},
"place_id" : "ChIJ2eUgeAK6j4ARbn5u_wAGqWA",
"types" : [ "street_address" ]
}
],
"status" : "OK"
}
如何从json中检索formatted_address
等下的Lat
,Long
和geometry>Location
。大多数json教程都是用简单的json文件解释的。
请帮助我,帮助我找到一些好的教程
答案 0 :(得分:3)
实际上,简单的JSON和复杂的JSON并没有那么不同。你可以说复杂的JSON 里面有很多更简单的JSON ,所以如果你知道如何从简单的数据中获取数据,你最终知道如何从复合体中获取数据< / p>
无论如何,将JSON对象视为dictionaries
,将JSON数组视为lists
。要从dicts获取数据,请使用key
作为值。要从列表中获取数据,请使用值的index
(位置)。
所以,在你的情况下:
lat = json["results"][0]["geometry"]["location"]["lat"]
long = json["results"][0]["geometry"]["location"]["lng"]
和
formatted_address = json["results"][0]["formatted_address"]
注意如何通过键进行导航,以及在从键中检索值时如何更深入
答案 1 :(得分:0)