Question

如何提取孩子的ID值（即followerID1，followerID2 ......）？ firebase的结构如下：

Followers:{
    USER_ID:{
        followerID1 = false;
        followerID2 = true;
        followerID3 = true;
    }
}

我在xCode中执行以下操作，但它显示了USER_ID下的整个节点：

self.databaseRef.child("Followers").child(self.USER_ID).Value, withBlock: { (snapshot:FIRDataSnapshot) in
          self.userFollowDump = snapshot
 })

谢谢！我是firebase的新手：）

Answer 1

试试这个： -

Swift 3

FIRDatabase.database().reference().child("Followers").child(FIRAuth.auth()!.currentUser!.uid).observeSingleEvent(of: .value, with: { (snapshot) in
        if let userDict = snapshot.value as? [String:AnyObject]{
            for each in userDict{
                let follwerID = each.0 as! String // Every follwers ID.
            }
        }
    })

如果您正在寻找值 true 的 followerId 。

    FIRDatabase.database().reference().child("Followers").child(FIRAuth.auth()!.currentUser!.uid).queryOrderedByValue().queryEqual(toValue: true).observeSingleEvent(of: .value, with: {(snap) in
        if let snapDict = snap.value as? [String:AnyObject]{
            for each in snapDict{

                print(each.key)
            }
        }
    })

Swift 2

FIRDatabase.database().reference().child("Followers").child(FIRAuth.auth()!.currentUser!.uid).observeSingleEventOfType(.Value, withBlock: { (snapshot) in
 if let userDict = snapshot.value as? [String:AnyObject]{
      for each in userDict{
         let follwerID = each.0 as! String // Every follwers ID.
         }
     }
  })

但如果您正在寻找 true

的 followerId

FIRDatabase.database().reference().child("Followers").child(FIRAuth.auth()!.currentUser!.uid).queryOrderedByValue().queryEqualToValue(true).observeSingleEventOfType(.Value, withBlock: {(snap) in
     if let snapDict = snap.value as? [String:AnyObject]{
       for each in snapDict{

            print(each.key)
        }
    }
})

Firebase：如何从子节点swift中提取子键值

1 个答案: