我创建了这个脚本,仅适用于名称为" jan"的工作表。 - 无论我如何尝试,它都可以在所有工作表上运行。谁能帮我检查一下我做错了什么?
function onEdit() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheetByName("jan");
var r = sheet.getActiveCell();
if( r.getColumn() == 3 ) {
var nextCell = r.offset(0, 1);
if( nextCell.getValue() === '' )
var time = new Date();
time = Utilities.formatDate(time, "GMT", "dd/MM");
nextCell.setValue(time);
};
};
答案 0 :(得分:0)
尝试:
function onEdit() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getActiveSheet();
if (sheet.getName() == "jan") {
// DO SOMETHING TO "jan"
Logger.log("working on sheet jan...");
}
}
答案 1 :(得分:0)
将上述内容与您正在做的事情放在一起:
function onEdit(e) {
var activeSheet = e.source.getActiveSheet();
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheetByName("jan");
var r = sheet.getActiveCell();
if( r.getColumn() == 3 && activeSheet.getName()=="jan") {
var nextCell = r.offset(0, 1);
if( nextCell.getValue() === '' )
var time = new Date();
time = Utilities.formatDate(time, "GMT", "dd/MM");
nextCell.setValue(time);
};
};