Question

我正在尝试实现https://neo4j.com/blog/moving-relationships-neo4j/指针功能，以便将其用作团队订单计算机。请参阅http://imgur.com/a/MViF0了解模型。我正在使用这个密码查询。

 MERGE (list:LIST)
 WITH list
 MATCH (u) WHERE ID(u) IN [421, 419, 420]
 MERGE (team:TEAM{name: u.name})
 MERGE (team)-[:PARTOF]->(list)
 WITH collect(team)as elems,list
      FOREACH (n IN RANGE(0, LENGTH(elems)-2) |
 FOREACH (prec IN [elems[n]] |
 FOREACH (next IN [elems[n+1]] |
 MERGE (prec)-[:NEXT]->(next))))
 with list
 MATCH (elem:TEAM) WHERE NOT (elem)<-[:NEXT]-()
 MERGE (list)-[:POINTER]->(elem)

现在这很好用，但我只有一个问题。这一行：

MATCH (u) WHERE ID(u) IN [421, 419, 420]

返回按ID排序的原始团队，但我想通过[421,419,420]模式中的模式定义我的顺序，就像一个

的函数

return * order by my array input.

请记住，它应该适用于任何数量的团队，这只是一个例子。而我原来的团队节点并没有被标记为团队，而是其他东西，所以我们每次都会复制。感谢任何投入，谢谢。

Answer 1

尝试使用语句＆＃34;展开＆＃34;：

MERGE (list:LIST)
WITH list
UNWIND [421, 419, 420] as uid
MATCH (u) WHERE id(u) = uid
MERGE (team:TEAM{name: u.name})
...

[更新]当然，可以手动了解每个节点的订单：

MERGE (list:LIST)
WITH list, [3871013, 3871011, 3871012] as ids
MATCH (u) WHERE ID(u) IN ids
WITH list, u, 
     FILTER(x in RANGE(0,size(ids)-1) WHERE ids[x] = id(u)) as orderIndex 
     ORDER BY orderIndex[0] // Sort by node position in the array of identifiers
MERGE (team:TEAM{name: u.name})
...

neo4j按输入的数组顺序匹配节点

1 个答案: