Question

我想将参数传递给索引函数，如果参数不是，则重定向到主页。我也添加了自定义路线。我在哪里错过了代码？

$route['main/(:any)'] = 'main/index/'; // looks like has a mistake

www.example.com - ＆gt;当deafult index function

时

www.example.com/females - ＆gt;当deafult index具有字符串参数'female'

时

class Main extends CI_Controller {

public function index($gender) {  

  load->view('inc/header_view');

  if((isset($gender)) && ($gender =='female')){ 

    $this->load->view('female_view');

  } else {

    $this->load->view('female_view');
  }
}

Answer 1

您可以通过以下代码

来实现此目的

class Main extends CI_Controller {

public function index($gender="") {  

  if($gender == "")
  {
     $this->load->view('home');

  } else {

    $this->load->view('female_view');
  }
}

正如您所提到的，要让此网址正常工作www.example.com＆amp; www.example.com/females，您需要在routes.php中添加以下内容

$route['default_controller'] = "main";
$route['(:any)'] = 'main/index/$1';

如果有任何疑问，请告诉我

Answer 2

您应该尝试

$route['main'] = 'main/index'; 

$route['main/(:any)'] = 'main/index/$1';

或者您可以使用uri细分。

http://www.codeigniter.com/user_guide/libraries/uri.html?highlight=uri%20segments#CI_URI::segment

如何将参数传递给索引和自定义路由

2 个答案: