Question

最近iOS有iOS 10及更新版本开发人员有一些变化，现在我们无法检查允许完全访问权限我们之前的做法如下所示

-(BOOL)isOpenAccessGranted{
   return [UIPasteboard generalPasteboard];
 }

我搜索了最新的Developer Guide for UIPasteboard，但无法解决。有没有人有适当的解决方案。

Answer 1

iOS11及以上版本很简单。

iOS10解决方案：检查所有可复制的类型，如果其中一个可用，则您具有完全访问权限，否则不会。

- Swift 4.2 -

override var hasFullAccess: Bool
{
    if #available(iOS 11.0, *){
        return super.hasFullAccess// super is UIInputViewController.
    }

    if #available(iOSApplicationExtension 10.0, *){
        if UIPasteboard.general.hasStrings{
            return  true
        }
        else if UIPasteboard.general.hasURLs{
            return true
        }
        else if UIPasteboard.general.hasColors{
            return true
        }
        else if UIPasteboard.general.hasImages{
            return true
        }
        else  // In case the pasteboard is blank
        {
            UIPasteboard.general.string = ""

            if UIPasteboard.general.hasStrings{
                return  true
            }else{
                return  false
            }
        }
    } else{
        // before iOS10
        return UIPasteboard.general.isKind(of: UIPasteboard.self)
    }
}

Answer 2

我已经解决了这个问题。 iOS 10.0 和 Swift 3.0

func isOpenAccessGranted() -> Bool {

    if #available(iOSApplicationExtension 10.0, *) {
        UIPasteboard.general.string = "TEST"

        if UIPasteboard.general.hasStrings {
            // Enable string-related control...
            UIPasteboard.general.string = ""
            return  true
        }
        else
        {
            UIPasteboard.general.string = ""
            return  false
        }
    } else {
        // Fallback on earlier versions
        if UIPasteboard.general.isKind(of: UIPasteboard.self) {
            return true
        }else
        {
            return false
        }

    }

}

像这样使用： -

if (isOpenAccessGranted())
{
   print("ACCESS : ON")
}
else{
   print("ACCESS : OFF")
}

Answer 3

对于朋友，在Objective-C中搜索解决方案，这是

NSOperatingSystemVersion operatingSystem= [[NSProcessInfo processInfo] operatingSystemVersion];

if (operatingSystem.majorVersion>=10) {
    UIPasteboard *pasteboard = [UIPasteboard generalPasteboard];
    pasteboard.string = @"Hey";

    if (pasteboard.hasStrings) {
        pasteboard.string = @"";
        return true;
    }
    else
    {
        pasteboard.string = @"";
        return false;
    }
}
else
{
    return [UIPasteboard generalPasteboard];
}

P.S。：这只是一种解决方法

Answer 4

在iOS 10 Swift 3.0和iOS 9上测试

使用#available(iOS 10.0, *)代替#available(iOSApplicationExtension 10.0, *)

func isOpenAccessGranted() -> Bool {
    if #available(iOS 10.0, *) {
        var originalString = UIPasteboard.general.string
        if(!(originalString != nil)){
            originalString = ""
        }
        UIPasteboard.general.string = "Test"

        if UIPasteboard.general.hasStrings {
            UIPasteboard.general.string = originalString
            return true
        }else{
            return false
        }
    }else{
        return UIPasteboard.general.isKind(of: UIPasteboard.self)
    }
}

Answer 5

Swift 3

BitConverter.ToSingle

Answer 6

有点hacky，但是可以用：

快捷键5

static func isOpenAccessGranted() -> Bool {
    let inputVC = UIInputViewController()
    return inputVC.hasFullAccess
}

允许完全访问权限检查键盘iOS10

6 个答案: