Question

UPDATE newsreactions
SET newsreactions.enabled = '0'
FROM newsreactions
INNER JOIN users ON newsreactions.memberId = users.id
WHERE users.active =  '0' AND users.comment LIKE  '%spam%'

出于某种原因，我收到语法错误：

1064 - 您的SQL语法出错;查看与您的MySQL服务器版本相对应的手册，以便在'FROM newsreactions INNER JOIN用户附近使用正确的语法ON newsreactions.memberId = users.id WHERE u'在第3行

虽然无法理解。如果我将update和set替换为select，则可以正常使用。

Answer 1

错误1064是MySQL语法错误。正确的MySQL语法是：

UPDATE newsreactions nr INNER JOIN
       users u
       ON nr.memberId = u.id
    SET nr.enabled = 0
WHERE u.active =  0 AND u.comment LIKE '%spam%';

注意：

JOIN符合UPDATE条款。
表别名使查询更容易编写和阅读。
我猜测enabled和active确实是数字值。如果是这样，请不要使用单引号。

Answer 2

Obj = { "elements":[ {"name":"something","id":"v1-234"}, {"name":"somethingElse","id":"v1-239"} ], "paging":{ "next" : "100", "total": "2000" }, "linked"={ "partners":[ {"id":"82","name":"A"}, {"id":"83","name":"B"} ], "instructors": [ {"id":"11232","name":"alex"}, {"id":"11432","name":"boob"} ] } }子句应该在join子句之前，并且MySQL中不应该有set子句：

from

内部联接的sql更新和

2 个答案: