Question

请考虑以下事项：

Date.parse('August 28th 2016');
NaN

等什么？什么是获得日期时间的正确方法，所以我可以做类似的事情：

data.sort((a, b) =>
      Date.parse(Object.keys(a)[0]) -
      Date.parse(Object.keys(b)[0]))

Object.keys(a)[0] // => August 28th 2016

那么......又怎么样了？

Answer 1

我建议使用momentjs来更轻松地处理日期。您的任务可以通过以下方式完成：

#include <iostream>
#include <iomanip>
#include <limits>

using namespace std;

int main() {
    int i = 4;
    double d = 4.0;
    string s = "HackerRank ";

    // Declare second integer, double, and String variables.
    int n;
    double d2;
    string str;

    // Read and save an integer, double, and String to your variables.
    cin >> n;
    cin >> d2;

    cin.ignore();

    getline(cin, str);

    // Print the sum of both integer variables on a new line.
    cout << i + n << endl;


    // Print the sum of the double variables on a new line.
    cout << d + d2 << endl;

    // Concatenate and print the String variables on a new line
    cout << s << str << endl;

    // The 's' variable above should be printed first.

    return 0;
}

var dates = [moment('August 28th 2016' ,'MMMM Do YYYY'),moment('August 22nd 2016' ,'MMMM Do YYYY'),moment('August 12th 2016' ,'MMMM Do YYYY')];

dates.sort(function(a,b) {
  return a.isAfter(b);
});

console.log(dates);

或者更好 - 如果您的对象的键现在是字符串：

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.15.0/moment-with-locales.min.js"></script>

var dates = ['August 28th 2016','August 22nd 2016','August 12th 2016'];

dates.sort(function(a,b) {
  return moment(a,'MMMM Do YYYY').isAfter(moment(b,'MMMM Do YYYY'));
});

console.log(dates);

Date.parse给了我NAN的字符串日期...等什么？

1 个答案: