这是我拥有的json字符串。
{
"?xml" : {
"@version" : "1.0",
"@encoding" : "UTF-8"
},
"DataFeed" : {
"@FeedName" : "issuerDetails",
"SecurityDetails" : {
"Security" : {
"SecurityID" : {
"@idValue" : "AAPL-NSDQ",
"@fiscalYearEnd" : "2016-12-31T00:00:00.00"
},
"FinancialModels" : {
"FinancialModel" : [{
"@id" : "780",
"@name" : "Estimates - Energy",
"@clientCode" : "A",
"Values" : [{
"@name" : "EBITDA",
"@clientCode" : "EBITDA",
"@currency" : "C$",
"Value" : [{
"@year" : "2014",
"#text" : "555.64"
}, {
"@year" : "2015",
"#text" : "-538.986"
}, {
"@year" : "2016",
"#text" : "554.447"
}, {
"@year" : "2017",
"#text" : "551.091"
}, {
"@year" : "2018",
"#text" : "0"
}
]
}, {
"@name" : "EPS",
"@clientCode" : "EPS",
"@currency" : "C$",
"Value" : [{
"@year" : "2014",
"#text" : "0"
}, {
"@year" : "2015",
"#text" : "-1.667"
}, {
"@year" : "2016",
"#text" : "-1.212"
}, {
"@year" : "2017",
"#text" : "0.202"
}, {
"@year" : "2018",
"#text" : "0"
}
]
}, {
"@name" : "CFPS",
"@clientCode" : "CFPS",
"@currency" : "C$",
"Value" : [{
"@year" : "2014",
"#text" : "3.196"
}, {
"@year" : "2015",
"#text" : "-0.207"
}, {
"@year" : "2016",
"#text" : "0.599"
}, {
"@year" : "2017",
"#text" : "2.408"
}, {
"@year" : "2018",
"#text" : "0"
}
]
}
]
}
]
}
}
}
}
}
如何为2015年,2016年,2017年的EPS选择#text
数据?这是我到目前为止的查询:
JObject jsonFeed = JObject.Parse(jsonText);
var query = from security in jsonFeed.SelectTokens("DataFeed.SecurityDetails.Security")
.SelectMany(i => i.ObjectsOrSelf())
let finModels = security.SelectTokens("FinancialModels.FinancialModel")
.SelectMany(s => s.ObjectsOrSelf()).FirstOrDefault()
where finModels != null
select new
{
FinModelClientCode = (string)finModels.SelectToken("Values[1].@clientCode"),
FinModelYear2015 = (string)finModels.SelectToken("Values[1].Value[1].@year"),
FinModelValue2015 = (string)finModels.SelectToken("Values[1].Value[1].#text"),
FinModelYear2016 = (string)finModels.SelectToken("Values[1].Value[2].@year"),
FinModelValue2016 = (string)finModels.SelectToken("Values[1].Value[2].#text"),
FinModelYear2017 = (string)finModels.SelectToken("Values[1].Value[3].@year"),
FinModelValue2017 = (string)finModels.SelectToken("Values[1].Value[3].#text"),
};
这是我使用的jsonExtensions:
public static class JsonExtensions
{
public static IEnumerable<JToken> DescendantsAndSelf(this JToken node)
{
if (node == null)
return Enumerable.Empty<JToken>();
var container = node as JContainer;
if (container != null)
return container.DescendantsAndSelf();
else
return new[] { node };
}
public static IEnumerable<JObject> ObjectsOrSelf(this JToken root)
{
if (root is JObject)
yield return (JObject)root;
else if (root is JContainer)
foreach (var item in ((JContainer)root).Children())
foreach (var child in item.ObjectsOrSelf())
yield return child;
else
yield break;
}
public static IEnumerable<JToken> SingleOrMultiple(this JToken source)
{
IEnumerable<JToken> arr = source as JArray;
return arr ?? new[] { source };
}
}
问题是EPS对于下一家公司并不总是处于同一位置?所以,我希望查询搜索EPS客户端代码&amp;返回上述年份的值,希望使用DRY方法。你能帮我完成我的查询吗?
注意:我实际上是在下载XML字符串,将其转换为JSON然后解析它。
XmlDocument doc = new XmlDocument();
doc.LoadXml(xmlString);
jsonText = Newtonsoft.Json.JsonConvert.SerializeXmlNode(doc);
JObject jsonFeed = JObject.Parse(jsonText);
答案 0 :(得分:5)
我认为最简单的方法是将json反序列化为具体对象,如下面的
var root = JsonConvert.DeserializeObject<RootObject>(jsonstring);
你的模型将是
public class SecurityID
{
[JsonProperty("@idValue")]
public string IdValue { get; set; }
[JsonProperty("@iscalYearEnd")]
public string FiscalYearEnd { get; set; }
}
public class Time
{
[JsonProperty("@year")]
public string Year { get; set; }
[JsonProperty("#text")]
public string Text { get; set; }
}
public class FinancialModelItem
{
[JsonProperty("@name")]
public string Name { get; set; }
[JsonProperty("@clientCode")]
public string ClientCode { get; set; }
[JsonProperty("@currency")]
public string Currency { get; set; }
public List<Time> Value { get; set; }
}
public class FinancialModel
{
[JsonProperty("@id")]
public string Id { get; set; }
[JsonProperty("@name")]
public string Name { get; set; }
[JsonProperty("@clientCode")]
public string ClientCode { get; set; }
public List<FinancialModelItem> Values { get; set; }
}
public class FinancialModels
{
public List<FinancialModel> FinancialModel { get; set; }
}
public class Security
{
public SecurityID SecurityID { get; set; }
public FinancialModels FinancialModels { get; set; }
}
public class SecurityDetails
{
public Security Security { get; set; }
}
public class DataFeed
{
[JsonProperty("@FeedName")]
public string FeedName { get; set; }
public SecurityDetails SecurityDetails { get; set; }
}
public class Xml
{
[JsonProperty("@version")]
public string Version { get; set; }
[JsonProperty("@encoding")]
public string Encoding { get; set; }
}
public class RootObject
{
[JsonProperty("?xml")]
public Xml Xml { get; set; }
public DataFeed DataFeed { get; set; }
}
您的查询现在将是
var result = root.DataFeed.SecurityDetails.Security.FinancialModels.FinancialModel
.FirstOrDefault()?.Values
.FirstOrDefault(x => x.Name == "EPS")
.Value
.Where(x => new[] { "2015", "2016", "2017" }.Contains(x.Year))
.Select(x => x.Text)
.ToList();
答案 1 :(得分:2)
怎么样:
var jsonFeed = JObject.Parse(jsonText);
var epsToken = jsonFeed.SelectToken("$..Values[?(@.@name=='EPS')]");
var year2014 = epsToken.SelectToken("Value[?(@.@year=='2014')].#text").ToString();
var year2015 = epsToken.SelectToken("Value[?(@.@year=='2015')].#text").ToString();
var year2016 = epsToken.SelectToken("Value[?(@.@year=='2016')].#text").ToString();
var year2017 = epsToken.SelectToken("Value[?(@.@year=='2017')].#text").ToString();
更通用的方法,它将选择所有年份和值:
var jsonFeed = JObject.Parse(jsonText);
var epsToken = jsonFeed.SelectToken("$..Values[?(@.@name=='EPS')]");
var years = epsToken.SelectToken("Value")
.Select(i => new
{
Year = i.Value<string>("@year"),
Value = i.Value<decimal>("#text")
});
$..
表示我们将从文档的开头搜索遍历所有节点并搜索Values
令牌@name
等于EPS
。基本上,在?(
和)
之间,您正在进入令牌必须符合才能被选中的条件。 @
表示当前节点,因此@.@name
会转换为current node which has child node with name '@name'
(我们在示例中将其与EPS
进行比较)。
您可以在此处找到有关JPath
的更多信息:http://goessner.net/articles/JsonPath。
注意到您更新了处理XML的答案,因此基本原则保持不变:
XmlDocument doc = new XmlDocument();
doc.LoadXml(xmlString);
var epsNode = doc.SelectSingleNode("//Values[@name='EPS']");
var years = epsNode.SelectNodes("Value")
.Cast<XmlNode>()
.Select(i => new
{
Year = i.Attributes["year"].Value,
Value = decimal.Parse(i.InnerText)
});
Haven未在您的XML上对其进行测试。此外,请注意i.Attributes["year"]
可能是null
,因此也要对此进行测试。
答案 2 :(得分:2)
你开始使用XML数据......为什么不把它作为XML数据处理呢。
var name = "EPS";
var years = new[] { "2015", "2016", "2017" };
var xpath = $"//Values[@name='{name}']/Value[{String.Join(" or ", years.Select(y => $"@year='{y}'"))}]";
var values = doc.XPathSelectElements(xpath).Select(e => (decimal)e);
否则,如果你必须坚持使用它作为json,那么你可以这样做:
var name = "EPS";
var years = new[] { "2015", "2016", "2017" };
var jpath = $"$..Values[?(@.@name=='{name}')].Value[?({String.Join(" || ", years.Select(y => $"@.@year=='{y}'"))})].#text";
var values = jsonFeed.SelectTokens(jpath).Select(v => (decimal)v);
答案 3 :(得分:1)
如果您确定这将是json格式,您可以创建一个表示json对象的类,并让一些库(如JconConvert)进行解析。从那里开始应该很容易。