Question

我使用Swift 3.0开发了Slack集成的iOS应用程序。我如何通过登录过程：

func loginToSlackWithSafariBrowser() {
    let scope = "channels%3Awrite+users%3Aread"
    let clientId = "...myClientId"
    let redirect_uri = "myAppDeepLink://"
    let authURL = NSURL(string: "https://slack.com/oauth/authorize?client_id=\(clientId)&scope=\(scope)&redirect_uri=\(redirect_uri)")

    guard let url  = authURL else { return }
    UIApplication.shared.openURL(url as URL)
}

然后Safari应用程序打开，我输入凭证，点击＆＃34;授权＆＃34;和＃34;在您的应用程序中打开？＆＃34; 我点击是并重定向到我的应用程序，我从Slack代码发送下一个请求：

        //AppDelegate.swift
extension UIApplicationDelegate {
func application(_ application: UIApplication, open url: URL, sourceApplication: String?, annotation: AnyObject) -> Bool {
    self.exchangeCodeInURL(codeURL: url as NSURL)
    return true
}

func exchangeCodeInURL(codeURL : NSURL) {
    let clientId = "...myClientId"
    let clientSecret = "...myclientSecret"
    if let code = codeURL.query {
        let request = NSMutableURLRequest(url: NSURL(string: "https://slack.com/api/oauth.access?client_id=\(clientId)&client_secret=\(clientSecret)&code=\(code)") as! URL)
        request.httpMethod = "GET"
        request.setValue("application/json", forHTTPHeaderField: "Accept")
        URLSession.shared.dataTask(with: request as URLRequest, completionHandler: { (data, response, error) -> Void in
            print(response)
            guard let unwrappedData = data else {return}
            do {
                if let rootObject = try JSONSerialization.jsonObject(with: unwrappedData, options: []) as? NSDictionary {
                    //Save and handle the token
                    print(rootObject)
                }
            }
            catch {
                print(error)
            }
        }).resume()
    }
}

}

代码在Xcode 8 beta中工作，但是当我更新到Xcode 8时，在从Slack网站重定向后没有调用扩展中的函数。

有什么问题？有没有更好的方法来通过Slack登录过程？

Answer 1

您可能需要在将代码发送到oauth.access GET之前解析代码。当我在XCode 8和Swift 2.3上运行时，我的代码包含＆＃34; code = Xxxx＆amp; state =＆＃34;。

我正在处理同样的问题，并感谢您的问题，因为它帮助我开始了身份验证过程。

Answer 2

好的，错误真的很愚蠢......而不是

func application(_ application: UIApplication, open url: URL, sourceApplication: String?, annotation: AnyObject) -> Bool

已弃用

func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool

必须实施。

所以这应该在你的 AppDelegate

中

 func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey : Any]? = nil) -> Bool { //don't miss to implement this!
    return true
}

func application(_ app: UIApplication, open url: URL, options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool{
    self.exchangeCodeInURL(codeURL: url)
    return true
}

func exchangeCodeInURL(codeURL : URL) {
    let clientId = "...myClientId"
    let clientSecret = "...myclientSecret"
    if let code = codeURL.query {
        guard let url = URL(string: "https://slack.com/api/oauth.access?client_id=\(clientId)&client_secret=\(clientSecret)&\(code)") else {return} //as code = "code=Xxxx&state=" you don't have to extract code from string, this query works good
        let request = NSMutableURLRequest(url: url)
        request.setValue("application/json", forHTTPHeaderField: "Accept")
        request.httpMethod = "GET"
        URLSession.shared.dataTask(with: request as URLRequest, completionHandler: { (data, response, error) -> Void in
            print(response)
            guard let unwrappedData = data else {return}
            do {
                if let rootObject = try JSONSerialization.jsonObject(with: unwrappedData, options: []) as? NSDictionary {
                    //Save and handle the token
                    print(rootObject)
                }
            }
            catch {
                print(error)
            }
        }).resume()
    }
}

Slack Login无效。 Swift 3.0

2 个答案: