如何避免在ReduxThunk的操作中复制代码？

Question

如何避免在这样的动作中重复相同的constance？谢谢！

export const createLabelAction = (name, color) => {
    return (dispatch, getState) => {
        const authorization = getState().get('authorization').authorization;
        const repositoryOwner = getState().get('repositoryLoader').repositoryOwner;
        const selectedRepository = getState().get('repositoryLoader').selectedRepository;
        const updateInProcess = getState().get('repoLabels').updateInProcess;
        return api.createLabel(authorization, repositoryOwner, selectedRepository, name, color)
            .then(result => {
                //  Status: 201 Created
                if(result.status === 201) {
                    //  if updating not processing
                    if (!updateInProcess) {
                        dispatch(fetchListLabelsForRepositoryAction(repositoryOwner, selectedRepository));
                    }
               }
            })
            .catch(err => console.log(err));
    }
}

export const updateLabelAction = (labelUrl, newName, newColor) => {
    return (dispatch, getState) => {
        const authorization = getState().get('authorization').authorization;
        const repositoryOwner = getState().get('repositoryLoader').repositoryOwner;
        const selectedRepository = getState().get('repositoryLoader').selectedRepository;
        const updateInProcess = getState().get('repoLabels').updateInProcess;
        return api.updateLabel(authorization, labelUrl, newName, newColor)
            .then(result => {
                //  Status: 200 OK
                if(result.status === 200) {
                    //  if updating not processing
                    if (!updateInProcess) {
                        dispatch(fetchListLabelsForRepositoryAction(repositoryOwner, selectedRepository));

                    }
                }
            })
            .catch(err => console.log(err));
    }
}

我有两个以上的功能，很难。如果我改变选择器。我必须改变行动中的所有常数。我可以把它们放在一个地方吗？