Question

我想循环每一个约会并把它放在json中：

[
   {
      "id":"1",
      "title":"Test 1",
      "start":"2016-09-16 12:00:00",
      "end":"2016-09-16 14:00:00",
      "allDay":false
   },

   {
       "id":"2",
       "title":"Test 2",
       "start":"2016-09-15 12:00:00",
       "end":"2016-09-15 14:00:00",
       "allDay":false
   }
]

我在数据库中有一个表appointments。

id | title  | appointment_date_start | appointment_date_end |
-------------------------------------------------------------
1  | Test 1 | 2016-09-16 12:00:00    | 2016-09-16 14:00:00  |
2  | Test 2 | 2016-09-15 12:00:00    | 2016-09-15 14:00:00  |

在我的feed.blade.php中，我获得了所有数据。所以我能做到：

@foreach ($appointments as $appointments)

    {{ $appointment->id }}
    {{ $appointment->title }}
    {{ $appointment->appointment_date_start }}
    {{ $appointment->appointment_date_end }}

@endforeach

这将输出数据库中的数据。但是我如何在数组中预先处理它呢？

像

$event_array[] = array(
    'id' => {{ $appointment->id }},
    'title' => {{ $appointment->gender }},
    'start' => {{ $appointment->appointment_date_start }},
    'end' => {{ $appointment->appointment_date_end }},
    'allDay' => false
);

修改

我在公共职能部门尝试了这个

public function feed()
{   
    $feed = Appointment::all();
    return $feed->toJson();
    return view('appointments/feed');
}

这就是我得到的

{
    id: 35,
    user_id: 1,
    gender: "men",
    appointment_date_start: "2016-09-14 20:00:00",
    appointment_date_end: "2016-09-14 20:40:00",
    created_at: "2016-09-16 08:16:16",
    updated_at: "2016-09-16 08:16:16"
}

我需要删除gender, created_at and updated_at，并且应该启动appointment_date_start并且应该结束appointment_date_end吗？这可能吗？

Answer 1

你可以去{{ $appointments->toJson() }}，这就是你想要的吗？

Answer 2

如果要删除created_at和updated_at，只需在从数据库中提取数据时选择属性：

$feed = Appointment::select('id', 'user_id', 'appointment_date_start as start', 'appointment_date_end as end')->get(); 
// leave created_at and updated_at
// select('old as new') to change the attribute name

然后使用json_encode

将数组编码为json

return json_encode($feed);

将数据循环到json中？

2 个答案: