Question

我最近尝试创建一种在第二个线程中打开ProgressDialog的简单方法，因此如果主线程冻结，对话框将继续工作。

这是班级：公共类ProgressDialogThread扩展了Thread { public Looper ThreadLooper; public Handler mHandler;

public ProgressDialog ThreadDialog; public Context DialogContext; public String DialogTitle; public String DialogMessage;

public ProgressDialogThread(Context mContext, String mTitle, String mMessage)
 {
  DialogContext = mContext;
  DialogTitle = mTitle;
  DialogMessage = mMessage;
 }

 public void run()
 {
  Looper.prepare();
  ThreadLooper = Looper.myLooper();

  ThreadDialog = new ProgressDialog(DialogContext);
  ThreadDialog.setTitle(DialogTitle);
  ThreadDialog.setMessage(DialogMessage);
  ThreadDialog.show();

  mHandler = new Handler();

  Looper.loop();
 }

 public void Update(final String mTitle, final String mMessage)
 {
  while(mHandler == null)
   synchronized(this) {
    try { wait(10); } 
    catch (InterruptedException e) {
     Log.d("Exception(ProgressDialogThread.Update)", e.getMessage() == null ? "MISSING MESSAGE" : e.getMessage());
    }
   }

  mHandler.post(new Runnable(){
   @Override
   public void run() {
    ThreadDialog.setTitle(mTitle);
    ThreadDialog.setMessage(mMessage);
   }});
 }

 public void Dismiss() 
 {
  while(ThreadDialog == null || mHandler == null)
   synchronized(this) {
    try { wait(10); } 
    catch (InterruptedException e) {
     Log.d("Exception(ProgressDialogThread.Dismiss)", e.getMessage() == null ? "MISSING MESSAGE" : e.getMessage());
    }
   }

  mHandler.post(new Runnable(){
   @Override
   public void run() {
    ThreadDialog.dismiss();
   }});
 }

 public void Continue() 
 {
  while(ThreadLooper == null || mHandler == null)
   synchronized(this) {
    try { wait(10); } 
    catch (InterruptedException e) {
     Log.d("Exception(ProgressDialogThread.Continue)", e.getMessage() == null ? "MISSING MESSAGE" : e.getMessage());
    }
   }

  mHandler.post(new Runnable(){
   @Override
   public void run() {
    ThreadLooper.quit();
   }});
 }

然而，它有时可以完美地工作，但有时候应用程序最终会冻结并崩溃。

以下是使用示例：

ProgressDialogThread thread = new ProgressDialogThread(this, "Loading", "Please wait...");
thread.start();
// Do Stuff
thread.Dismiss();
thread.Continue();

它会产生很多警告甚至有时会发生一些崩溃：

例如。处理程序：向死线程发送消息....

和例外情况一样 ANR ...... 原因：keyDispatchingTimedOut

感谢您的帮助，亚历克斯。

Answer 1

当想要在Android上的单独线程中执行操作时，您应该查看AsyncTask类。您可以在此处阅读：http://developer.android.com/resources/articles/painless-threading.html

Google搜索（或在此处搜索Stack Overflow）也会为您提供有关如何使用它的大量信息，但上述链接还不够：）

Android 2.2：ProgressDialog在第二个线程中冻结

1 个答案: