Question

我有一个问题。如何从原型扩展中访问TeslaModelS中的我的变量？

或者我的插件模式错了吗？

我想将我的应用的不同区域分开，而不是将其全部放在一个大文件中

＆＃13;

var TeslaModelS = function () {
    this.numWheels = 4;
    this.manufacturer = 'Tesla';
    this.make = 'Model S';

    this.Drive.pressGasPedal();
}

TeslaModelS.prototype = function () {
    var _this = this;

    var Drive = {
        go: function () {
          // HOW CAN I GET RED AND WRITE ACCESS TO MY VARS IN TeslaModelS ??
            console.log(_this.numWheels)
        },

        stop: function () {
        }
    }

    return {
        Drive: {
            pressBrakePedal: Drive.stop,
            pressGasPedal: Drive.go
        }
    }

}();

var i = new TeslaModelS();

＆＃13;

Answer 1

您无法使用您创建的结构。我建议使用更正常的结构：

＆＃13;

// The constructor function
var TeslaModelS = function() {
  this.numWheels = 4;
  this.manufacturer = 'Tesla';
  this.make = 'Model S';

  this.pressGasPedal();
};

TeslaModelS.prototype.pressGasPedal = function() {
  console.log(this.numWheels);
};

TeslaModelS.prototype.pressBrakePedal = function() {
};

var i = new TeslaModelS();

＆＃13;

但是如果你不想，如果你真的想要那个Drive对象，你需要在不同的Drive对象上创建这些函数的绑定版本。实例：

＆＃13;

// The functions you'll bind each time
var Drive = {
  go: function() {
    console.log(this.numWheels)
  },

  stop: function() {}
};

// The constructor function
var TeslaModelS = function() {
  this.numWheels = 4;
  this.manufacturer = 'Tesla';
  this.make = 'Model S';

  // Create a Drive object for this instance with the functions bound
  // to `this`
  this.Drive = {
    pressGasPedal: Drive.go.bind(this),
    pressBrakePedal: Drive.stop.bind(this)
  };

  this.Drive.pressGasPedal();
}

var i = new TeslaModelS();

＆＃13;

我怎样才能从上层范围访问变量--javascript

1 个答案: